The gravitational force on the rider is:
- Way up: equal to mg
- Way down: equal to mg
Explanation:
The choices are missing: find them in the attached figure.
The force of gravity acting on a body is a force directed downward (towards the Earth's centre) and whose magnitude is
where
m is the mass of the body
g is the acceleration due to gravity
The value of g is approximately constant near the Earth's surface and it is
During the ride, the mass of the rider, m, remains constant. This means that the magnitude of the gravitational force, mg, exerted on the rider remains constant during the rider.
Therefore, the correct answer is
- Way up: equal to mg
- Way down: equal to mg
Learn more about force of gravity:
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Yes a small child can play with fat child in the seesaw because if the the load distance is decreased the effort will increase. That's means if the distance between the fat boy and the fulcrum is decreased the small child needs less effort.so,he can play
Answer:
(a) Rm = 268.4 m
(b) f = 6
Explanation:
The horizontal range of a projectile is given by the following formula:
R = V₀² Sin 2θ/g
(a)
For moon:
R = Range on moon = Rm
V₀ = Launch Speed = 28 m/s
θ = Launch Angle = 17°
g = acceleration due to gravity on moon = (9.8 m/s²)/6 = 1.63 m/s²
Therefore,
Rm = (28 m/s)²Sin (2*17°)/(1.63 m/s²)
<u>Rm = 268.4 m</u>
(b)
For Earth:
R = Range on Earth = Re
V₀ = Launch Speed = 28 m/s
θ = Launch Angle = 17°
g = acceleration due to gravity on Earth = 9.8 m/s²
Therefore,
Re = (28 m/s)²Sin (2*17°)/(9.8 m/s²)
Re = 44.7 m
Therefore.
f = Rm/Re = 268.4 m/44.7 m
<u>f = 6</u>
To calculate the acceleration of the wooden block, we use the expression F=ma where F is the force applied, m is the mass of the object and a is the acceleration. We calculate as follows:
F = ma
4.9 = 0.5a
a = 9.8
Hope this answers the question. Have a nice day.
observer is standing at distance d = 60 m south from the intersection
cyclist is travelling at speed v = 10 m/s
now after t = 8 s its displacement from intersection is given by
so the position of cyclist makes an angle with the observer
now the component of velocity of cyclist along the line joining its position with the observer is given as
here
so at this instant cyclist is moving away with speed 8 m/s
