A can of soft drink at room temperature is put into the refrigerator so that it will cool. Would you model the can of soft drink
1 answer:
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Answer:
T₂ =602 °C
Explanation:
Given that
T₁ = 227°C =227+273 K
T₁ =500 k
Gauge pressure at condition 1 given = 100 KPa
The absolute pressure at condition 1 will be
P₁ = 100 + 100 KPa
P₁ =200 KPa
Gauge pressure at condition 2 given = 250 KPa
The absolute pressure at condition 2 will be
P₂ = 250 + 100 KPa
P₂ =350 KPa
The temperature at condition 2 = T₂
We know that
T₂ = 875 K
T₂ =875- 273 °C
T₂ =602 °C
Answer:
a.
b.
Explanation:
The force existing between two charges is given as
where q= charge,
k=constant
r= distance between the two charges
Note: this force can either be repulsive or attractive force depending on the charges involve. it is repulsive if they are similar charge and it is attractive if it is opposite charges.
Also the charge of an electron is
A. we first determine the magnitude force between the -4nC and the electron
this force will be repulsive force and it points away from the electron i.e points towards the +ve x-axis
for the -5.50nC the distance between them is 0.600m as can be seen in the diagram the magnitude of the force is
this this force will be repulsive force and it points away from the electron i.e points towards the -ve x-axis.
The total net force on the electron is thus
b. at distance of x=1.20m, this is shown on the diagram below (attachment 2)
we first determine the magnitude force between the -4nC and the electron
this force will be repulsive force and it points away from the electron i.e points towards the +ve x-axis.
for the -5.50nC the distance between them is 0.4m as can be seen in the diagram the magnitude of the force is
this this force will be repulsive force and it points away from the electron i.e points towards the +ve x-axis.
The total net force on the electron is thus
