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Law Incorporation [45]
2 years ago
9

A can of soft drink at room temperature is put into the refrigerator so that it will cool. Would you model the can of soft drink

as a closed system or as an open system?
Physics
1 answer:
Gennadij [26K]2 years ago
7 0

Answer:

A can of soft drink being transferred from the room temperature to a refrigerator is a closed system.

Explanation:

When a can of soft drink is transferred to a refrigerator from room temperature then only energy transfer can occur i.e. the heat of soft drink is absorbed by the refrigerator but the quantity of mass packed in the can does not gets altered.

From the thermodynamic point of view a closed system is one in which the mass content of the system does not changes only the energy transfer can take place through the boundary of the system.

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Specific agricultural uses of water are all of the following except _____. evaporation growing crops raising livestock cleaning
Tamiku [17]
Evaporation.............
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2 years ago
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When were Earth’s landmasses first recognizable as the continents we know today? 10 million years ago 135 million years ago 180
Bess [88]

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b

Explanation:

i took the test

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1 year ago
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Although it shouldn’t have happened, on a dive i fail to watch my spg and run out of air. if my buddy is close by, my best optio
leva [86]

Answer:

B ) Ascend using my buddy alternative air source / make an emergency Ascent

Explanation:

From the description it can be seen his buddy is close by of which he can easily use the alternative air source. Also we can see that he is closer to the water surface than his buddy, of which controlled emergency swimming ascent is highly favourable in this condition.

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2 years ago
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A block of mass 2.00 kg is initially at rest at x=0 on a slippery horizontal surface for which there is no friction. Starting at
Allisa [31]

Answer:

   x = 1,185 m ,     t = 4/3 s ,  F = - 4 N

Explanation:

For this exercise we use Newton's second law

         F = m a = m dv /dt

        β - α t = m dv / dt

        dv = (β – α t) dt

     

We integrate

        v = β t - ½ α t²

We evaluate between the lower limits v = v₀ for t = 0 and the upper limit v = v for t = t

       v-v₀ = β t - ½ α t²

the farthest point of the body is when v = v₀ = 0

  0 = β t - ½ α t²

  t = 2 β / α

  t = 2 4/6

  t = 4/3 s

Let's find the distance at this time

   v = dx / dt

   dx / dt = v₀ + β t - ½ α t2

   dx = (v₀ + β t - ½ α t2) dt

We integrate

   x = v₀ t + ½ β t - ½ 1/3 α t³

   x = v₀ 4/3 + ½ 4 (4/3)² - 1/6 6 (4/3)³

The body comes out of rest

    x = 3.5556 - 2.37

    x = 1,185 m

The value of force is

    F = β - α t

    F = 4 - 6 4/3

   F = - 4 N

8 0
1 year ago
A 26 cm object is 18 cm in front of a plane mirror. A ray of light strikes the object and is reflected off the mirror at a 42-de
matrenka [14]

Answer:

42 degrees, virtual image, same size as the object (26 cm)

Explanation:

The law of reflection states that:

- When a ray of light is incident on a flat surface (such as the plane mirror), the angle of reflection is equal to the angle of incidence

So, since in this case the angle of incidence is 42 degrees, the angle of reflection is also 42 degrees.

Moreover, the image formed by a plane mirror is always:

- Virtual (on the same side as the object)

- The same size as the object

So in this case, since the object's size is 26 cm, the image's size is also 26 cm.

8 0
2 years ago
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