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Feliz [49]
2 years ago
6

Although it shouldn’t have happened, on a dive i fail to watch my spg and run out of air. if my buddy is close by, my best optio

n is to another option is to if i’m in shallow water and the surface is closer than my buddy.a) ascend using my buddy's alternate air source / make a controlled emergency swimming ascent
b) ascend using my buddy's alternate air source / make an buoyant emergency ascent
c) make a normal ascent / ascend using my buddy's alternate air source
d) make a controlled emergency swimming ascent / make a normal ascent
Physics
2 answers:
sukhopar [10]2 years ago
8 0

Complete Question:

Although it shouldn't have happened, on a dive I fail to watch my SPG and run out of air. If my buddy is close by, my best option is to __________. Another option is to _____________, if I'm in shallow water and the surface is closer than my buddy.

NB: The options still remain as written in the question

Answer:

a) ascend using my buddy's alternate air source / make a controlled emergency swimming ascent

Explanation:

Since I have exhausted my own air source, my buddy's alternate air source will be the only saver if he is close by. Controlled emergency swimming accent is used if the swimmer's buddy is far but the swimmer is close to the surface. Buoyant emergency ascent can only be used if the swimmer is deep away from the surface and needs to make it to the surface.

leva [86]2 years ago
5 0

Answer:

B ) Ascend using my buddy alternative air source / make an emergency Ascent

Explanation:

From the description it can be seen his buddy is close by of which he can easily use the alternative air source. Also we can see that he is closer to the water surface than his buddy, of which controlled emergency swimming ascent is highly favourable in this condition.

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Bbk

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8 0
1 year ago
A submarine completed a 450 km training with an average speed of 50 km/h. For the first 180 km, it travelled at an average speed
Kryger [21]

Answer:

45km/hr

Explanation:

Total distance=450km

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Total time= distance/speed

=450/50

=9hrs

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Distance b=450-180=270km

Speed b=?

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4 0
2 years ago
You are using a hydrogen discharge tube and high quality red and blue light filters as the light source for a Michelson interfer
boyakko [2]

Answer:

final displacement = +24484.5 nm

Explanation:

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Δr = 2d2 - 2d1 = 150λ1

So, 2d2 - 2d1 = 150λ1

Dividing both sides by 2 to get;

d2 - d1 = 75λ1 - - - - eq1

Where;

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Now, the path difference between the two waves when 114 bright spots were observed is;

Δr = 2d'2 - 2d1 = 114λ1

2d'2 - 2d1 = 114λ1

Divide both sides by 2 to get;

d'2 - d1 = 57λ1

Where;

d'2 is the new position of the movable mirror from the splitter

Now, the displacement of the moveable mirror is (d2 - d'2). To get this, we will subtract eq2 from eq1.

(d2 - d1) - (d'2 - d1) = 75λ1 - 57λ2

d2 - d1 - d'2 + d1 = 75λ1 - 57λ2

d2 - d'2 = 75λ1 - 57λ2

We are given;

(λ1 = 656.3 nm) and λ2 = 434.0 nm.

Thus;

d2 - d'2 = 75(656.3) - 57(434)

d2 - d'2 = +24484.5 nm

5 0
2 years ago
A teacher sets up a stand carrying a convex lens of focal length 15 cm at 20.5 cm mark on the optical bench. She asks the studen
Brums [2.3K]
We get the clearest image if there is no magnification. When we have no magnification the image and real object have the same size.
If we look at the diagram that I  attached we can see that:
\frac{h_i}{h_0}=\frac{d_i}{d_0}
Two triangles that I marked are similar and from this we get:
\frac{h_i}{h_0}=\frac{d_i-f}{f}
The image and the object must have the same height so we get:
\frac{h_i}{h_0}=\frac{d_i-f}{f};h_i=h_0\\
1=\frac{d_i-f}{f}\\
d_i=2f
This tells how far the screen should be from the lens. 
The position of the screen on the optical bench is:
S=20.5cm+2f=20.5+2\cdot 15cm=50.5cm

8 0
2 years ago
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Answer: -2 km

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-2 km

3 0
2 years ago
Read 2 more answers
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