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trasher [3.6K]
2 years ago
8

A certain liquid has a density of 2.67 g/cm3. 1340 g of this liquid would occupy a volume of ________ l.

Physics
2 answers:
qaws [65]2 years ago
8 0
Volume = mass/density = 1340/2.67 = 501.87 cm^3 = 0.50187L
ch4aika [34]2 years ago
6 0

Answer: 0.5018L

Explanation: The relationship between mass and density is given by the following equation:

Volume = Mass/Density

The density given shows that 2.67g of the liquid would occupy a cm³ volume at every point in time.

Given this, total volume occupied would be

Mass = 1340g

Density = 2.67g/cm³

V =?

V = 1340/2.67

V = 501.87cm³ = 501.87/1000 = 0.5018L

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Rus_ich [418]
M1 descending
−m1g + T = m1a 

m2 ascending
m2g − T = m2a

this gives :
(m2 − m1)g = (m1 + m2)a 

a = (m2 − m1)g/m1 + m2
   = (5.60 − 2)/(2 + 5.60) x 9.81 
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5 0
2 years ago
(d) A beam of white light shines onto a sheet of white paper. An identical beam of light shines onto a mirror. The light is scat
irakobra [83]
QUESTION:-A beam of white light shines onto a sheet of white paper. An identical beam of light shines onto a mirror. The light is scattered from the paper and reflected from the mirror.
Describe how scattering by paper and reflection by a mirror are different from each other.


ANSWER: Scattering sends or reflects light from each point on the object in all directions, whereas reflection sends light from each point on the object in one direction only (or to one point)
5 0
2 years ago
A car is traveling at 20 meters/second and is brought to rest by applying brakes over a period of 4 seconds. What is its average
frez [133]
 (u) = 20 m/s 
(v) = 0 m/s 
<span> (t) = 4 s 
</span>
<span>0 = 20 + a(4) 

</span><span>4 x a = -20 
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so, the answer is <span>-5 m/s^2. or -5 meter per second</span>
8 0
2 years ago
Read 2 more answers
Small frogs that are good jumpers are capable of remarkable accelerations. One species reaches a takeoff speed of3.7 m/s in60 ms
MAVERICK [17]

We know that acceleration is change in velocity by time taken for that change.

In this case velocity change is 3.7 m/s

Time taken for this change = 60 ms = 6 *10^{-3} seconds

So acceleration of frog  = \frac{3.7}{60*10^{-3}}

                                       = 61.66 m/s^2

So acceleration of frog is 61.66 m/s^2

o it is evident that frog is capable of remarkable accelerations.

8 0
2 years ago
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The air in a pipe resonates at 150 Hz and 750 Hz, one of these resonances being the fundamental. If the pipe is open at both end
Xelga [282]

Answer:

Explanation:

Two frequencies with magnitude 150 Hz and 750 Hz are given

For Pipe open at both sides

fundamental frequency is 150 Hz as it is smaller

frequency  of pipe is given by

f=\frac{nv}{2L}

where L=length of Pipe

v=velocity of sound

f=150\ Hz for n=1

and f=750 is for n=5

thus there are three resonance frequencies for n=2,3 and 4

For Pipe closed at one end

frequency is given by

f=\frac{(2n+1)}{4L}\cdot v

for n=0

f_1=\frac{v}{4L}

f_1=150\ Hz

for n=2

f_2=\frac{5v}{4L}

Thus there is one additional resonance corresponding to n=1 , between f_1 and f_2

8 0
2 years ago
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