A pump moves water horizontally at a rate of 0.02 m3/s. Upstream of the pump where the pipe diameter is 90 mm, the pressure is 1
20 kPa. Downstream of the pump where the pipe diameter is 30 mm, the pressure is 400 kPa. If the loss in energy across the pump due to fluid friction effects is 170 N.m/kg, determine the hydraulic efficiency of the pump.
1 answer:
Answer:
the efficiency of hydralic is 79.88%
Explanation:
convert mm to m
1mm = (1/1000)m
diameter of pipe upsteam
d₁= 90mm= 0.09m
diameter of pipe downsteam
d₂= 30mm = 0.03m
finding velocity of upsteam
recall Q=A₁V₁
V₁=Q/A₁
V₁=3.14m/s
velocity of downsteam
V₂= Q/A₂
V₂= 28.29m/s
mass flow rate
m= ρQ
ρ is the density of water
m = 1000× 0.02
m= 20kg/s
the efficiency of hydralic is 79.88%
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Answer:
It increased by a factor of 3.
Explanation:
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where
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g is the gravitational acceleration
h is the heigth of the object relative to some reference point (for instance, the ground)
As we see from the formula, the gravitational potential energy is directly proportional to the mass, m: therefore, if the mass of the cylinder is increased by a factor 3, then the gravitational potential energy will also increase by a factor 3.