Answer: The Ampère -Max-well law
Explanation:
The Ampère -Max-well law relates magnetic flux and electric current. It determines the relationship between current in association with a magnetic field and also magnetic field in association to related current.
Answer:
Connect C₁ to C₃ in parallel; then connect C₂ to C₁ and C₂ in series. The voltage drop across C₁ the 2.0-μF capacitor will be approximately 2.76 volts.
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Explanation:
Consider four possible cases.
<h3>Case A: 12.0 V.</h3>

In case all three capacitors are connected in parallel, the
capacitor will be connected directed to the battery. The voltage drop will be at its maximum: 12 volts.
<h3>Case B: 5.54 V.</h3>
![-3.0\;\mu\text{F}-[\begin{array}{c}-{\bf 2.0\;\mu\text{F}}-\\-1.5\;\mu\text{F}-\end{array}]-](https://tex.z-dn.net/?f=-3.0%5C%3B%5Cmu%5Ctext%7BF%7D-%5B%5Cbegin%7Barray%7D%7Bc%7D-%7B%5Cbf%202.0%5C%3B%5Cmu%5Ctext%7BF%7D%7D-%5C%5C-1.5%5C%3B%5Cmu%5Ctext%7BF%7D-%5Cend%7Barray%7D%5D-)
In case the
capacitor is connected in parallel with the
capacitor, and the two capacitors in parallel is connected to the
capacitor in series.
The effective capacitance of two capacitors in parallel is the sum of their capacitance: 2.0 + 1.5 = 3.5 μF.
The reciprocal of the effective capacitance of two capacitors in series is the sum of the reciprocals of the capacitances. In other words, for the three capacitors combined,
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What will be the voltage across the 2.0 μF capacitor?
The charge stored in two capacitors in series is the same as the charge in each capacitor.
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Voltage is the same across two capacitors in parallel.As a result,
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<h3>Case C: 2.76 V.</h3>
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Similarly,
- the effective capacitance of the two capacitors in parallel is 5.0 μF;
- the effective capacitance of the three capacitors, combined:
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Charge stored:
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Voltage:
.
<h3 /><h3>Case D: 4.00 V</h3>
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Connect all three capacitors in series.
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For each of the three capacitors:
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For the
capacitor:
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From the conservation of linear momentum of closed system,
Initial momentum = final momentum
Mass of the student, M = 59 kg
Mass of the laser boat, m = 42 kg
Initial speed of student + laser boat, u =0
Final speed of laser boat, v = 1.5 m/s
Final speed of the student = V
(M+m) u =M V +m v
0 = (59 kg) V + (42 kg) (1.5m/s)
V = - 1.06 m/s
Thus, the speed of the student is 1.06 m/s in the opposite direction of the motion of boat.
The Correct answer is (B), Because the reject each other.