answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Scrat [10]
1 year ago
6

A pump moves water horizontally at a rate of 0.02 m3/s. Upstream of the pump where the pipe diameter is 90 mm, the pressure is 1

20 kPa. Downstream of the pump where the pipe diameter is 30 mm, the pressure is 400 kPa. If the loss in energy across the pump due to fluid friction effects is 170 N.m/kg, determine the hydraulic efficiency of the pump.

Physics
1 answer:
victus00 [196]1 year ago
6 0

Answer:

the efficiency of hydralic is 79.88%

Explanation:

convert mm to m

1mm = (1/1000)m

diameter of pipe upsteam

d₁= 90mm= 0.09m

diameter of pipe downsteam

d₂= 30mm = 0.03m

finding velocity of upsteam

recall Q=A₁V₁

V₁=Q/A₁

V₁=3.14m/s

velocity of downsteam

V₂= Q/A₂

V₂= 28.29m/s

mass flow rate

m= ρQ

ρ is the density of water

m = 1000× 0.02

m= 20kg/s

the efficiency of hydralic is 79.88%

You might be interested in
To show that displacement current is necessary to make Ampère's law consistent for a charging capacitor Ampère's law relates the
Sladkaya [172]

Answer: The Ampère -Max-well law

Explanation:

The Ampère -Max-well law relates magnetic flux and electric current. It determines the relationship between current in association with a magnetic field and also magnetic field in association to related current.

7 0
2 years ago
A couch is pushed with a horizontal force of 80 N and moves the couch a
Lapatulllka [165]

Answer:

400 J

Explanation:

Work = force × distance

W = (80 N) (5 m)

W = 400 J

5 0
1 year ago
Read 2 more answers
Given three capacitors, c1 = 2.0 μf, c2 = 1.5 μf, and c3 = 3.0 μf, what arrangement of parallel and series connections with a 12
Lesechka [4]

Answer:

Connect C₁ to C₃ in parallel; then connect C₂ to C₁ and C₂ in series. The voltage drop across C₁ the 2.0-μF capacitor will be approximately 2.76 volts.

-1.5\;\mu\text{F}-[\begin{array}{c}-{\bf 2.0\;\mu\text{F}}-\\-3.0\;\mu\text{F}-\end{array}]-.

Explanation:

Consider four possible cases.

<h3>Case A: 12.0 V.</h3>

-\begin{array}{c}-{\bf 2.0\;\mu\text{F}-}\\-1.5\;\mu\text{F}- \\-3.0\;\mu\text{F}-\end{array}-

In case all three capacitors are connected in parallel, the 2.0\;\mu\text{F} capacitor will be connected directed to the battery. The voltage drop will be at its maximum: 12 volts.

<h3>Case B: 5.54 V.</h3>

-3.0\;\mu\text{F}-[\begin{array}{c}-{\bf 2.0\;\mu\text{F}}-\\-1.5\;\mu\text{F}-\end{array}]-

In case the 2.0\;\mu\text{F} capacitor is connected in parallel with the 1.5\;\mu\text{F} capacitor, and the two capacitors in parallel is connected to the 3.0\;\mu\text{F} capacitor in series.

The effective capacitance of two capacitors in parallel is the sum of their capacitance: 2.0 + 1.5 = 3.5 μF.

The reciprocal of the effective capacitance of two capacitors in series is the sum of the reciprocals of the capacitances. In other words, for the three capacitors combined,

\displaystyle C(\text{Effective}) = \frac{1}{\dfrac{1}{C_3}+ \dfrac{1}{C_1+C_2}} = \frac{1}{\dfrac{1}{3.0}+\dfrac{1}{2.0+1.5}} = 1.62\;\mu\text{F}.

What will be the voltage across the 2.0 μF capacitor?

The charge stored in two capacitors in series is the same as the charge in each capacitor.

Q = C(\text{Effective}) \cdot V = 1.62\;\mu\text{F}\times 12\;\text{V} = 19.4\;\mu\text{C}.

Voltage is the same across two capacitors in parallel.As a result,

\displaystyle V_1 = V_2 = \frac{Q}{C_1+C_2} = \frac{19.4\;\mu\text{C}}{3.5\;\mu\text{F}} = 5.54\;\text{V}.

<h3>Case C: 2.76 V.</h3>

-1.5\;\mu\text{F}-[\begin{array}{c}-{\bf 2.0\;\mu\text{F}}-\\-3.0\;\mu\text{F}-\end{array}]-.

Similarly,

  • the effective capacitance of the two capacitors in parallel is 5.0 μF;
  • the effective capacitance of the three capacitors, combined: \displaystyle C(\text{Effective}) = \frac{1}{\dfrac{1}{C_2}+ \dfrac{1}{C_1+C_3}} = \frac{1}{\dfrac{1}{1.5}+\dfrac{1}{2.0+3.0}} = 1.15\;\mu\text{F}.

Charge stored:

Q = C(\text{Effective}) \cdot V = 1.15\;\mu\text{F}\times 12\;\text{V} = 13.8\;\mu\text{C}.

Voltage:

\displaystyle V_1 = V_3 = \frac{Q}{C_1+C_3} = \frac{13.8\;\mu\text{C}}{5.0\;\mu\text{F}} = 2.76\;\text{V}.

<h3 /><h3>Case D: 4.00 V</h3>

-2.0\;\mu\text{F}-1.5\;\mu\text{F}-3.0\;\mu\text{F}-.

Connect all three capacitors in series.

\displaystyle C(\text{Effective}) = \frac{1}{\dfrac{1}{C_1} + \dfrac{1}{C_2}+\dfrac{1}{C_3}} =\frac{1}{\dfrac{1}{2.0} + \dfrac{1}{1.5}+\dfrac{1}{3.0}} =0.667\;\mu\text{F}.

For each of the three capacitors:

Q = C(\text{Effective})\cdot V = 0.667\;\mu\text{F} \times 12\;\text{V} = 8.00\;\mu\text{C}.

For the 2.0\;\mu\text{F} capacitor:

\displaystyle V_1=\frac{Q}{C_1} = \frac{8.00\;\mu\text{C}}{2.0\;\mu\text{F}} = 4.0\;\text{V}.

6 0
1 year ago
a 59kg physics student jumps off the back of her laser sailboat (42kg). after she jumps the laser is found to be travelling at 1
evablogger [386]

From the conservation of linear momentum of closed system,

Initial momentum = final momentum

Mass of the student, M = 59 kg

Mass of the laser boat, m = 42 kg

Initial speed of student + laser boat, u =0

Final speed of laser boat, v = 1.5 m/s

Final speed of the student = V

(M+m) u =M V +m v

0 = (59 kg) V + (42 kg) (1.5m/s)

V = - 1.06 m/s

Thus, the speed of the student is 1.06 m/s in the opposite direction of the motion of boat.

5 0
2 years ago
The diagram shows the electric field around two charged objects. What is the best conclusion about the charges that can be made
Lemur [1.5K]

The Correct answer is (B), Because the reject each other.

8 0
2 years ago
Read 2 more answers
Other questions:
  • A propagating wave in space with electric and magnetic components. These components oscillate at right angles to each other. It
    8·2 answers
  • The banking angle in a turn on the Olympic bobsled track is not constant, but increases upward from the horizontal. Coming aroun
    7·1 answer
  • The gravitational field of m1 is denoted by g1. Enter an expression for the gravitational field g1 at position la in terms of m1
    14·1 answer
  • Index of refraction
    15·1 answer
  • You have a device that needs a voltage reference of 3.0 V, but you have only a 9.0 V battery. Fortunately, you also have several
    12·2 answers
  • The image shows the electric field lines around two charged particles. 2 balls separated vertically. Lines with arrowheads run f
    14·2 answers
  • How to calculate area with force and pressure
    6·1 answer
  • A ball bearing of radius of 1.5 mm made of iron of density
    11·1 answer
  • Two strings are respectively 1.00 m and 2.00 m long. Which of the following wavelengths, in meters, could represent harmonics pr
    11·1 answer
  • Two pickup trucks each have a mass of 2,000 kg. The gravitational force between the trucks is 3.00 × 10-5 N. One pickup truck is
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!