Answer:
Part a)

Part b)
in this case the charge on the capacitor will become zero
Part c)

Part d)

Explanation:
As we know that first capacitor is charged with the battery and then it is connected to the inductor
So here we will have



Part a)
now since the total energy of capacitor is converted into the energy of inductor
so by energy conservation we can say

so maximum current is given as



Part b)
When current is maximum then whole energy of capacitor is converted into magnetic energy of inductor
So in this case the charge on the capacitor will become zero
Part c)
Time period of oscillation of charge between the plates and inductor is given as



now capacitor gets discharged first time after 1/4 of total time period

Part d)
Since time period is T and capacitor gets discharged two times in one complete time period of the motion
so first it will discharges in T/4 time
then next T/4 it will get charged again
then next T/4 time it will again discharged
so total time taken


F1 = G*m²/D²
<span>F = 2*F1*cos30° = 2*G*50²*cos30°/0.3² = 3.21E-6 </span>
<span>a = F/m = 3.21E-6/50 = 6.42E-8
Hope this helped!
STSN</span>
Answer:

Explanation:
The strain is defined as the ratio of change of dimension of an object under a force:

where
is the change in length of the object
is the original length of the object
In this problem, we have
and
, therefore the strain is

Answer:
Finally current will be
i = 0.35 A
Explanation:
As we know that power of the bulb is given by the formula

now we have

R = 240 ohm
so we have


now the current in the bulb is given as


now when length of the filament is double
so the resistance of the wire also gets double
so we have



now the current in the bulb is given as


