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A wire along the z axis carries a current of 4.9 A in the z direction Find the magnitude and direction of the force exerted on a
1 answer:
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Answer: (a) The gravitational force on the object at the North Pole of Neptune is 51.7N
(b) The apparent weight of the object at Neptune's equator is 50.4N
Explanation: Please see the attachments below
<h2>Answer: at an angle 
below the inclined plane.
</h2>
If we draw the <u>Free Body Diagram</u> for this situation (figure attached), taking into account only the gravity force in this case, we will see the weight of the block, which is directly proportional to the gravity acceleration
:
This force is directed vertically at an angle below the inclined plane, this means it has an X-component and a Y-component:
Therefore the correct option is c
Answer : The restoring force is directly proportional to the displacement of the block.
Explanation :
Restoring force is defined as the force that is exerted by the spring due to its mass.
Mathematically, the restoring force can be written as :
F = - k x
where,
k is the spring constant.
x is the displacement caused due to the mass.
Negative sign shows that the force is acting in opposite direction.
So, it is clear that the restoring force is directly proportional to the displacement of the block.
Hence, the correct option is (b) " The restoring force is directly proportional to the displacement of the block ".
Answer:
The centripetal force acting on the skater is <u>48.32 N.</u>
Explanation:
Given:
Radius of circular track is,
Tangential speed of the skater is,
Mass of the skater is,
We are asked to find the centripetal force acting on the skater.
We know that, when an object is under circular motion, the force acting on the object is directly proportional to the mass and square of tangential speed and inversely proportional to the radius of the circular path. This force is called centripetal force.
Centripetal force acting on the skater is given as:
Now, plug in the given values of the known quantities and solve for centripetal force, . This gives,
Therefore, the centripetal force acting on the skater is 48.32 N.