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wlad13 [49]
1 year ago
8

Two identical stunt professionals A and B stand on the roof of building 1. Person A steps off of the roof and falls vertically o

nto the solid ground. At the same instant, person B steps off the roof while holding onto a rope with its opposite end is fixed to building 2 of the same height. The rope is initially horizontal, and after swinging downward almost the same vertical distance as A fell, person B collides with the solid wall of building 2.
A. Which person will sustain more serious injuries, or will both sustain injuries of the same seriousness? Explain your reasoning.
Physics
1 answer:
Vladimir [108]1 year ago
6 0

Answer:

Both of the stunt professionals will sustain injuries of the same seriousness

Explanation:

We are being told that both stunt professionals are standing from the same height, therefore they will attain the same  equivalent speed at the bottom if we are to look at it from the principle of conservation of energy.

Now; According to principle of momentum; the momentum at which the first stunt professional A hits the ground be equal as the momentum with which stunt professional B will hit the wall.

Thus; both of the stunt professionals will sustain injuries of the same seriousness

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You are designing a generator with a maximum emf 8.0 V. If the generator coil has 200 turns and a cross-sectional area of 0.030
shutvik [7]

Answer:

7.1 Hz

Explanation:

In a generator, the maximum induced emf is given by

\epsilon= 2\pi NAB f

where

N is the number of turns in the coil

A is the area of the coil

B is the magnetic field strength

f is the frequency

In this problem, we have

N = 200

A=0.030 m^2

\epsilon=8.0 V

B = 0.030 T

So we can re-arrange the equation to find the frequency of the generator:

f=\frac{\epsilon}{2\pi NAB}=\frac{8.0 V}{2\pi (200)(0.030 m^2)(0.030 T)}=7.1 Hz

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1 year ago
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Most of the nutrients in the rainforest ecosystem are in the _____.
joja [24]
<span>The answer should be the vegitation. </span>
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1 year ago
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A toy rocket launcher can project a toy rocket at a speed as high as 35.0 m/s.
Anestetic [448]

Answer:

(a) 62.5 m

(b) 7.14 s

Explanation:

initial speed, u = 35 m/s

g = 9.8 m/s^2

(a) Let the rocket raises upto height h and at maximum height the speed is zero.

Use third equation of motion

v^{2}=u^{2}+2as

0^{2}=35^{2}- 2 \times 9.8 \times h

h = 62.5 m

Thus, the rocket goes upto a height of 62.5 m.

(b) Let the rocket takes time t to reach to maximum height.

By use of first equation of motion

v = u + at

0 = 35 - 9.8 t

t = 3.57 s

The total time spent by the rocket in air = 2 t = 2 x 3.57 = 7.14 second.

8 0
1 year ago
A monoatomic ideal gas undergoes an isothermal expansion at 300 K, as the volume increased from 0.010 m^3 to 0.040 m^3. The fina
Natali [406]

Answer:

A) 0.0 kJ

Explanation:

Change in the internal energy of the gas is a state function

which means it will not depends on the process but it will depends on the initial and final state

Also we know that internal energy is a function of temperature only

so here the process is given as isothermal process in which temperature will remain constant always

here we know that

\Delta U = \frac{3}{2}nR\Delta T

now for isothermal process since temperature change is zero

so change in internal energy must be ZERO

4 0
1 year ago
A child is riding a bike at a speed of 6m/s with a total kinetic energy of 1224J. If the mass of the child is 30kg, what is the
UkoKoshka [18]

Answer:

 Mass of bike = 38 kg.

Explanation:

Kinetic energy is given by the expression, KE = \frac{1}{2} mv^2, where m is the mass and v is the velocity.

Here speed of child riding bike = 6 m/s

Mass of child = 30 kg

Total kinetic energy = 1224 J

Let the mass of bike be, m kg

So, total mass of child and bike = (m + 30) kg

Substituting,

  1224 = \frac{1}{2}* (m+30)*6^2\\ \\ m+30=68\\ \\ m=38kg

So, mass of bike = 38 kg.

3 0
2 years ago
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