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wlad13 [49]
2 years ago
8

Two identical stunt professionals A and B stand on the roof of building 1. Person A steps off of the roof and falls vertically o

nto the solid ground. At the same instant, person B steps off the roof while holding onto a rope with its opposite end is fixed to building 2 of the same height. The rope is initially horizontal, and after swinging downward almost the same vertical distance as A fell, person B collides with the solid wall of building 2.
A. Which person will sustain more serious injuries, or will both sustain injuries of the same seriousness? Explain your reasoning.
Physics
1 answer:
Vladimir [108]2 years ago
6 0

Answer:

Both of the stunt professionals will sustain injuries of the same seriousness

Explanation:

We are being told that both stunt professionals are standing from the same height, therefore they will attain the same  equivalent speed at the bottom if we are to look at it from the principle of conservation of energy.

Now; According to principle of momentum; the momentum at which the first stunt professional A hits the ground be equal as the momentum with which stunt professional B will hit the wall.

Thus; both of the stunt professionals will sustain injuries of the same seriousness

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A uniform 1.0-N meter stick is suspended horizontally by vertical strings attached at each end. A 2.0-N weight is suspended from
fgiga [73]

Answer:

3.5 N

Explanation:

Let the 0-cm end be the moment point. We know that for the system to be balanced, the total moment about this point must be 0. Let's calculate the moment at each point, in order from 0 to 100cm

- Tension of the string attached at the 0cm end is 0 as moment arm is 0

- 2 N weight suspended from the 10 cm position: 2*10 = 20 Ncm clockwise

- 2 N weight suspended from the 50 cm position: 2*50 = 100 Ncm clockwise

- 1 N stick weight at its center of mass, which is 50 cm position, since the stick is uniform: 1*50 = 50 Ncm clockwise

- 3 N weight suspended from the 60 cm position: 3*60 = 180 Ncm clockwise

- Tension T (N) of the string attached at the 100-cm end: T*100 = 100T Ncm counter-clockwise.

Total Clockwise moment = 20 + 100 + 50 + 180 = 350Ncm

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For this to balance, 100 T = 350

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4 0
1 year ago
Romeo lanza suavemente guijarros a la ventana de julieta y quiere que los guijarros golpeen la ventana solo con con un component
Yuki888 [10]

Answer:

5.219\,\frac{m}{s}

Explanation:

Las condiciones del problema requieren el cálculo de la rapidez inicial de los guijarros. Se sabe que el componente vertical de la rapidez final es cero. Por tanto, el tiempo se determina a continuación: (The conditions of this problems require the calculation of the initial speed of the peebles. It is known that vertical component of the final speed is zero. Therefore, the time is determined herein:).

(0\,\frac{m}{s})^{2} = v_{o,y}^{2} - 2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.5\,m)

v_{o,y} = 9.395\,\frac{m}{s}

0\,\frac{m}{s} = 9.395\,\frac{m}{s} - \left(9.807\,\frac{m}{s^{2}} \right)\cdot \Delta t

\Delta t = 0.958\,s

Además, se determina el componente horizontal de la rapidez inicial (Likewise, the horizontal component of the initial speed is determined):

v_{o,x} = \frac{5\,m}{0.958\,s}

v_{o,x} = 5.219\,\frac{m}{s}

El guijarro tiene una rapidez de 5.219\,\frac{m}{s} cuando golpea la ventana (The peeble has a speed of  5.219\,\frac{m}{s} when it hits the window).

6 0
2 years ago
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