Answer:
2.13 s
Explanation:
Hi!
At t = 0s the rocket is at rest in its platform, so the intial speed is zero. I f the acceleration is A, then the height Y, and the speed V are:


We nedd to find time T during which the rocket engine provides upward acceleration. We know that:

With these 2 equations we can find A and T (dropping units for simplicity):

Answer:
0.0002 C.
Explanation:
Charge: This can be defined as the ratio of current to time flowing in a circuit. The S.I unit of charge is Coulombs (C)
Mathematically, charge can be expressed as
Q = CV ................................. Equation 1
Where Q = amount of charge, C = capacitance of the capacitor, V = potential difference across the plates.
Given: C = 2.0-μF = 2×10⁻⁶ F, V = 100 V.
Substitute into equation 1
Q = 2×10⁻⁶× 100
Q = 2×10⁻⁴ C
Q = 0.0002 C.
The amount of charge accumulated = 0.0002 C
Answer:
<em>You would use the kinematic formula:</em>

Explanation:
The upwards vertical motion is ruled by the equation:

Where:





Naming Δy = y - y₀, the equation becomes:

Then, you just need to substitute with Δy = 0.1m, t = 2s, and g = 9.8m/s², ans solve for the intital vertical velocity.
Answer:
The magnitude and direction of electric field midway between these two charges is
along AB.
Explanation:
Given that,
First charge 
second charge 
Distance = 20 cm
We need to calculate the electric field
For first charge,
Using formula of electric field

Put the valueinto the formula


Direction of electric field along AB
We need to calculate the electric field
For second charge,
Using formula of electric field

Put the valueinto the formula


Direction of electric field along AO
We need to calculate the net electric field at midpoint



Direction of net electric field along AB
Hence, The magnitude and direction of electric field midway between these two charges is
along AB.
4. Table 2.4 shows how the displacement of a runner changed
during a sprint race. Draw a displacement–time graph to show
this data, and use it to deduce the runner’s speed in the middle
of the race.
Table 2.4 Data for a sprinter during a race
Displacement
(m)
0 4 10 20 50 80 105
Time (s) 1 2 3 6 9 12