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slava [35]
2 years ago
9

A student has derived the following nondimensionally homogeneous equation:a=xt2−vt+Fmwhere v is a velocity's magnitude, a is an

acceleration's magnitude, t is a time, m is a mass, F is a force's magnitude, and x is a distance (or length). Which terms are dimensionally homogeneous?
Physics
1 answer:
ahrayia [7]2 years ago
6 0

Answer:

None of the terms are dimensionally homogeneous

Explanation:

a=xt^{2}-vt+Fm

dimensions from each term:

a:\frac{L}{T^{2}}

xt^{2}:L*T^{2}

vt:\frac{L}{T}*T=L

Fm:N*Kg=\frac{M*L}{T^{2}}*M=\frac{M^{2}*L}{T^{2}}

we observe that there are no terms with equal dimensions, that is to say none of the terms are dimensionally homogeneous

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Answer:

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2 years ago
At one point in the rescue operation, breakdown vehicle A is exerting a force of 4000 N and breakdown vehicle B is exerting a fo
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Answer:

1.) Magnitude = 5596 N

2.) Direction = 60 degrees

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