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qwelly [4]
1 year ago
5

if it takes 3.5 hours for the hogwarts express moving at a speed of 120 mi/hr to make it from platform 9 and 3/4 to hogwarts how

far apart are they? ​
Physics
1 answer:
Mila [183]1 year ago
4 0
Use the formula distance = rate * time. substitute in the values you know, which gives you distance = 120mph * 3.5hours. multiply 120 and 3.5 to get distance = 420 miles.
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A boy of mass 80 kg slides down a vertical pole, and a frictional force of 480 N acts on him. What is his acceleration as he sli
olga_2 [115]

Answer:

His acceleration is \overrightarrow{a}=4\frac{m}{s^{2}}

Explanation:

Newton's second law states that acceleration of a body is cause by a net force, the relation between them is:

\sum\overrightarrow{F}=m\overrightarrow{a}

On the boy there're acting two forces, his weight (W) that points downward and the frictional force (f) that points upward (they boy moves downward and friction always is opposite to movement). So \sum\overrightarrow{F}=\overrightarrow{W}+\overrightarrow{f} so (1) is:

\overrightarrow{W}+\overrightarrow{f}=m\overrightarrow{a}

Using the positive direction downward weight and gravitational acceleration(g) are positive and friction force is negative:

W-f=m\overrightarrow{a}, solving for a:

\overrightarrow{a}=\frac{W-f}{m}, weight is mg:

\overrightarrow{a}=\frac{mg-f}{m}=\overrightarrow{f}=\frac{(80kg)(10\frac{m}{s^{2}})-(480)}{80}

\overrightarrow{a}=4\frac{m}{s^{2}}

6 0
2 years ago
A physics teacher is designing a ballistics event for a science competition. The ceiling is 3.00m high, and the maximum velocity
krek1111 [17]

The launch proyectiles of kinematics  allows to find the maximum initial vertical velocity of the body so that it just reaches the ceiling

             v_{oy} = 2.56 m / s

       

Given parameters

  • The ceiling height y = 3 m

To find

  • Maximum vertical speed

Projectile launching is an application of kinematics where on the x axis there is no acceleration or and on the y axis the acceleration is the acceleration of gravity (g = 9.8 m / s ^ 2)

In this case, the maximum vertical velocity that the body can have occurs when the velocity on the ceiling is zero.

            v_y² = v_{oy}² - 2 g y

where v and v_{oy} are the initial velocity at the ceiling e initial, respectively, g the acceleration of gravity e and the height

           0 = v_{oy}² - 2 g y

           v_{oy} = \sqrt{2gy}

           v_{oy} = \sqrt{2 \ 9.8 \ 3}

           v_{oy} = 2.56 m / s

In conclusion with the kinematic of launch projectiles we can find the maximum initial vertical velocity of the body so that it just reaches the ceiling

             v_{oy} = 2.56 m / s

learn more about projectile launch here:

brainly.com/question/10903823

3 0
1 year ago
At some airports there are speed ramps to help passengers get from one place to another. A speed ramp is a moving conveyor belt
Volgvan

Answer:

It takes you 32.27 seconds to travel 121 m using the speed ramp

Explanation:

<em>Lets explain how to solve the problem</em>

- The speed ramp has a length of 121 m and is moving at a speed of

 2.2 m/s relative to the ground

- That means the speed of the ramp is 2.2 m/s

- You can cover the same distance in 78 seconds when walking on

  the ground

<em>Lets find your speed on the ground</em>

Speed = Distance ÷ Time

The distance is 121 meters

The time is 78 seconds

Your speed on the ground = 121 ÷ 78 = 1.55 m/s

If you walk at the same rate with respect to the speed ramp that

you walk on the ground

That means you walk with speed 1.55 m/s and the ramp moves by

speed 2.2 m/s

So your speed using the ramp = 2.2 + 1.55 = 3.75 m/s

Now we want to find the time you will take to travel 121 meters using

the speed ramp

Time = Distance ÷ speed

Distance = 121 meters

Speed 3.75 m/s

Time = 121 ÷ 3.75 = 32.27 seconds

It takes you 32.27 seconds to travel 121 m using the speed ramp

8 0
2 years ago
A roller coaster travels 200 feet horizontally and then rises 135 feet at an angle of 30 degrees above the ground. What is the m
Delvig [45]
Say the initial point is (0,0)

The final point is

x = 200 + 135*cos(30) = 200 + 135*sqrt(3)/2 = 316.91 ft
y = 135*sin(30) = 135/2 = 67.5 ft

Resultant vector = (316.91, 67.5) - (0,0) = 316.91, 67.5) ft
8 0
1 year ago
A 1700kg rhino charges at a speed of 50.0km/h. What is the magnitude of the average force needed to bring the rhino to a stop in
Ksivusya [100]
Force (N) = mass (kg) x velocity (m/s) / time (s)
7 0
2 years ago
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