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2 years ago

Which are methods of reducing exposure to ionizing radiation? Check all that apply.

2 answers:

8 0

<h2>Answer:Answer: using a lead apron during medical X-rays, using a short burst of X-rays to take an image, taking an image of the smallest possible area</h2>

Ionizing radiation is a type of energy released by atoms in the form of electromagnetic radiation (gamma rays or X-rays) or particles (alpha and beta particles or neutrons).

This is a product of the spontaneous disintegration of atoms, where the surplus energy emitted is a form of ionizing radiation.

In this context, people are exposed daily to ionizing radiation, both of natural origin (for example radon emanating from rocks and soil or cosmic rays that go through the Earth) or human, as for example by the generation of nuclear energy or for the medical use of radiation for diagnostic or therapeutic purposes.

In the latter case, the most common artificial sources of ionizing radiation are medical devices, such as X-ray machines.

In this regard, it should be noted that X-rays are dangerous, because they contain enough energy to trigger mutations in organs and tissues and cause cancer (the damage caused depends on the dose received or absorbed). That is why people who undergo X-rays should be exposed to a brief burst of this radiation to capture the image on a photographic film, as well as avoid taking very large areas of the body and the staff that works with them must be protected wearing a lead apron and be placed behind a thick concrete wall as these materials prevent these rays from passing.

Dominik [7]2 years ago

5 0

Answer: (1,4,5)

Explanation:

1, 4, 5, are the answers on edg

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Sayid made a chart listing data of two colliding objects. A 5-column table titled Collision: Two Objects Stick Together with 2 r

Alborosie

Answer:

6 m/s is the missing final velocity

Explanation:

From the data table we extract that there were two objects (X and Y) that underwent an inelastic collision, moving together after the collision as a new object with mass equal the addition of the two original masses, and a new velocity which is the unknown in the problem).

Object X had a mass of 300 kg, while object Y had a mass of 100 kg.

Object's X initial velocity was positive (let's imagine it on a horizontal axis pointing to the right) of 10 m/s. Object Y had a negative velocity (imagine it as pointing to the left on the horizontal axis) of -6 m/s.

We can solve for the unknown, using conservation of momentum in the collision: Initial total momentum = Final total momentum (where momentum is defined as the product of the mass of the object times its velocity.

In numbers, and calling $P_{xi}$ the initial momentum of object X and $P_{yi}$ the initial momentum of object Y, we can derive the total initial momentum of the system: $P_{total}_i=P_{xi}+P_{yi}= 300*10 \frac{kg*m}{s} -100*6\frac{kg*m}{s} =\\=(3000-600 )\frac{kg*m}{s} =2400 \frac{kg*m}{s}$

Since in the collision there is conservation of the total momentum, this initial quantity should equal the quantity for the final mometum of the stack together system (that has a total mass of 400 kg):

Final momentum of the system: $M * v_f=400kg * v_f$

We then set the equality of the momenta (total initial equals final) and proceed to solve the equation for the unknown(final velocity of the system):

$2400 \frac{kg*m}{s} =400kg*v_f\\\frac{2400}{400} \frac{m}{s} =v_f\\v_f=6 \frac{m}{s}$

7 0

2 years ago

Read 2 more answers

he first excited state of the helium atom lies at an energy 19.82 eV above the ground state. If this excited state is three-fold

bekas [8.4K]

Answer:

Relative population is 2.94 x 10⁻¹⁰.

Explanation:

Let N₁ and N₂ be the number of atoms at ground and first excited state of helium respectively and E₁ and E₂ be the ground and first excited state energy of helium respectively.

The ratio of population of atoms as a function of energy and temperature is known as Boltzmann Equation. The equation is:

$\frac{N_{1} }{N_{2} }$ = $\frac{g_{1}e^{\frac{-E_{1} }{KT} } }{g_{2}e^{\frac{-E_{2} }{KT} }}$

$\frac{N_{1} }{N_{2} }$ = $\frac{g_{1}e^{\frac{-(E_{1}-E_{2}) }{KT} } }{g_{2}}$

Here g₁ and g₂ be the degeneracy at two levels, K is Boltzmann constant and T is equilibrium temperature.

Put 1 for g₁, 3 for g₂, -19.82 ev for (E₁ - E₂) and 8.6x10⁵ ev/K for K and 10000 k for T in the above equation.

$\frac{N_{1} }{N_{2} }$ = $\frac{1\times e^{\frac{-(-19.82)}{8.6\times 10^{-5}\times 10000} } }{3}$

$\frac{N_{1} }{N_{2} }$ = 3.4 x 10⁹

$\frac{N_{2} }{N_{1} }$ = 2.94 x 10⁻¹⁰

5 0

2 years ago

When water flows from a faucet, the water molecules tend to join together and form a stream. Which of the four fundamental force

Yuki888 [10]

The fundamental force responsible for the cohesion of the water molecules leaving the faucet is the electromagnetic force.
Electromagnetic forces act on particles that are electrically charged. Water molecules are polar, which means that they have a positively charged end and a negatively charged end. This polarity arises from the fact that oxygen pulls the electrons in the molecule towards itself and attains a negative charge, while the hydrogen atoms in the molecules are left with a positive charge.

3 0

1 year ago

Read 2 more answers

The Slowing Earth The Earth's rate of rotation is constantly decreasing, causing the day to increase in duration. In the year 20

NNADVOKAT [17]

Answer:

The average angular acceleration of the Earth, α = 6.152 X 10⁻²⁰ rad/s²

Explanation:

Given data,

The period of 365 rotation of Earth in 2006, T₁ = 365 days, 0.840 sec

= 3.1536 x 10⁷ +0.840

= 31536000.84 s