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Iteru [2.4K]
2 years ago
5

Which are methods of reducing exposure to ionizing radiation? Check all that apply.

Physics
2 answers:
gulaghasi [49]2 years ago
8 0
<h2>Answer:Answer: using a lead apron during medical X-rays, using a short burst of X-rays to take an image, taking an image of the smallest possible area</h2>

Ionizing radiation is a type of energy released by atoms in the form of electromagnetic radiation (gamma rays or X-rays) or particles (alpha and beta particles or neutrons).

This is a product of the spontaneous disintegration of atoms, where the surplus energy emitted is a form of ionizing radiation.

In this context, people are exposed daily to ionizing radiation, both of natural origin (for example <u>radon</u> emanating from rocks and soil or <u>cosmic rays </u>that go through the Earth) or human, as for example by the generation of <u>nuclear energy</u> or for the <u>medical use of radiation</u> for diagnostic or therapeutic purposes.

In the latter case, the most common artificial sources of ionizing radiation are medical devices, such as X-ray machines.

In this regard, it should be noted that X-rays are dangerous, because they contain enough energy to trigger mutations in organs and tissues and cause cancer (<u>the damage caused depends on the dose received or absorbed</u>). That is why people who undergo X-rays should be exposed to a brief burst of this radiation to capture the image on a photographic film, as well as avoid taking very large areas of the body and the staff that works with them must be protected wearing a lead apron and be placed behind a thick concrete wall as these materials prevent these rays from passing.

Dominik [7]2 years ago
5 0

Answer: (1,4,5)

Explanation:

1, 4, 5, are the answers on edg

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8. Find the momentum of a photon in eV/c and in Kg. m/s if the wavelength is (a) 400nm ; (b) 1 Å = 0.1 nm, (c) 3 cm ; and (d) 2
nataly862011 [7]
We use the formula: p = E/c where E = hc / λ. hence, p = h/  λ. where h is the Planck's constant: 6.62607004 × 10-34 m2 kg / s and <span>λ is the wavelenght. 
</span>
a) p = <span>6.62607004 × 10-34 m2 kg / s / 0.1 x10^-9 m = 6.62607 x 10-24 m kg/s
</span>b) p = 6.62607004 × 10-34 m2 kg / s / 3 x10^-2 m = 2.20869 <span>x 10-32 m kg/s
</span>b) p = 6.62607004 × 10-34 m2 kg / s / 2 x10^-9 m = 3.3130 <span>x 10-25 m kg/s</span>
7 0
2 years ago
For each of the following systems and time intervals, select the appropriate version of
Ahat [919]

The heating coils in you toaster during the first five seconds after you turn the toaster on is Δ K = W + Q.


<span>Your automobile just before you fill it with gas until you pull away from the gas station at speed v is ΔK + ΔU + ΔEint = W + Q + TMW + TMT</span>   

 

<span>your body while you sit quietly and eat a peanut butter and jelly sandwich for lunch is ΔEint = Q + TET + TER
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your home during five minutes of a sunny afternoon while the temperature in the home remains fixed is ΔU = W + Q + TMW + TMT</span>  

 

 

4 0
2 years ago
A ruler of length 0.30m is pivoted at its centre. Equal and opposite forces of magnitude 2.0N are applied to the ends of the rul
kow [346]

Answer:

0.3858 Nm

Explanation:

The torque of the couple is the dot product of the force vector and the couple vector from 1 end of the ruler to the center. This equals to the product of their magnitude times the cosine() of the angle made by their direction:

T = \vec{F} \cdot \vec{s} = Fscos(50^0) = 2 * 0.3 * 0.643 = 0.3858 Nm

6 0
2 years ago
A mis-hit golf ball flies straight up in the air. Exactly 4.0 seconds later it lands right next to the tee. How high up did the
Juliette [100K]

Answer:

19.6 m

Explanation:

The total motion of the golf ball lasts 4.0 seconds: since the motion is symmetrical, it takes 2.0 s for the ball to reach the highest point and then another 2.0 s to land back on the tee.

Therefore, we can just analyze the second half of the motion that lasts

t = 2.0 s

During this time, the vertical distance covered by the ball is given by the equation:

d=ut+\frac{1}{2}gt^2

where

u = 0 is the initial velocity (zero because the ball starts from its highest point, where the velocity is zero)

t = 2.0 s

g = 9.8 m/s^2 is the acceleration of gravity

Solving for d, we find:

d=\frac{1}{2}(9.8)(2.0)^2=19.6 m

So, the ball reaches a maximum height of 19.6 m.

6 0
2 years ago
If the rocket has an initial mass of 6300 kg and ejects gas at a relative velocity of magnitude 2000 m/s , how much gas must it
Rzqust [24]

Answer:

The amount of gas that is to be released in the first second in other to attain an acceleration of  27.0 m/s2  is

      \frac{\Delta m}{\Delta t}   = 83.92 \ Kg/s

Explanation:

From the question we are told that

   The mass of the rocket is m = 6300 kg

   The velocity at gas is being ejected is  u =  2000 m/s

    The initial acceleration desired is a =  27.0 \  m/s

   The time taken for  the gas to be ejected is  t = 1 s

Generally this desired acceleration is mathematically represented as

        a = \frac{u *  \frac{\Delta m}{\Delta t} }{M -\frac{\Delta m}{\Delta t}* t}

Here \frac{\Delta m}{\Delta  t }  is the rate at which gas is being ejected with respect to time

Substituting values

      27 = \frac{2000 *  \frac{\Delta m}{\Delta t} }{6300 -\frac{\Delta m}{\Delta t}* 1}

=>   170100 -27* \frac{\Delta m}{\Delta t} = 2000 *  \frac{\Delta m}{\Delta t}

=>   170100  = 2027 *  \frac{\Delta m}{\Delta t}

=>   \frac{\Delta m}{\Delta t}   = \frac{170100}{2027}

=>   \frac{\Delta m}{\Delta t}   = 83.92 \ Kg/s

     

3 0
1 year ago
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