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Iteru [2.4K]
2 years ago
5

Which are methods of reducing exposure to ionizing radiation? Check all that apply.

Physics
2 answers:
gulaghasi [49]2 years ago
8 0
<h2>Answer:Answer: using a lead apron during medical X-rays, using a short burst of X-rays to take an image, taking an image of the smallest possible area</h2>

Ionizing radiation is a type of energy released by atoms in the form of electromagnetic radiation (gamma rays or X-rays) or particles (alpha and beta particles or neutrons).

This is a product of the spontaneous disintegration of atoms, where the surplus energy emitted is a form of ionizing radiation.

In this context, people are exposed daily to ionizing radiation, both of natural origin (for example <u>radon</u> emanating from rocks and soil or <u>cosmic rays </u>that go through the Earth) or human, as for example by the generation of <u>nuclear energy</u> or for the <u>medical use of radiation</u> for diagnostic or therapeutic purposes.

In the latter case, the most common artificial sources of ionizing radiation are medical devices, such as X-ray machines.

In this regard, it should be noted that X-rays are dangerous, because they contain enough energy to trigger mutations in organs and tissues and cause cancer (<u>the damage caused depends on the dose received or absorbed</u>). That is why people who undergo X-rays should be exposed to a brief burst of this radiation to capture the image on a photographic film, as well as avoid taking very large areas of the body and the staff that works with them must be protected wearing a lead apron and be placed behind a thick concrete wall as these materials prevent these rays from passing.

Dominik [7]2 years ago
5 0

Answer: (1,4,5)

Explanation:

1, 4, 5, are the answers on edg

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Physics help, please? :)
Svetllana [295]

Answer:

Explanation:

3. Newton’s third law explains how every action has an equal but opposite reaction, meaning that forces comes in pairs. While the locomotive’s wheels are pushing back against the ground as the action force, the ground is producing a reaction force towards the locomotive, propelling it forward. Another pair of forces that act on the locomotive is gravity and normal force. While gravity is pulling the locomotive towards the ground, the normal force the ground exerts on the locomotive is why the locomotive doesn’t fall through the ground.

4. The force of Earth’s gravity on the Sun is weaker than the force of the Sun’s gravity on Earth. The Sun’s attraction  affects the motion of Earth more than the Earth’s attraction affects the Sun’s motion because according to  Newton’s second law, force has mass as one of its factors. The Sun has a significantly higher mass than Earth,  meaning that its force of gravity would also be significantly higher. Newton’s third law is why the Earth doesn’t get  marginally closer to the Sun, stating that every action has an equal and opposite reaction. As the Sun is pulling  Earth towards itself, Earth is pulling away from the Sun.

8 0
1 year ago
A woman is applying 300N/m2 of pressure on to door with her hand. Her hand has area of 0.02m2. Work out the force being applied​
never [62]

Answer:

6N

Explanation:

Given parameters:

Pressure applied by the woman  = 300N/m²

Area = 0.02m²

Unknown:

Force applied  = ?

Solution:

Pressure is the force per unit area on a body

        Pressure  = \frac{force}{area}

         Force  = Pressure x area

        Force  = 300 x 0.02  = 6N

8 0
2 years ago
By constructing basic electric circuits, you will be able to measure current flow. With Ohm’s law in mind, what broad question a
andrezito [222]

Broad questions that we can answer by doing this experiment are <em><u>the effects of electric current</u></em>

<h3>Further explanation</h3>

Electric current is the amount of electric charge that flows each unit of time

Electric current occurs due to the movement of electrons due to the difference in potential or voltage (from high potential to low potential) between two points

Electrons will flow through the conducting wire that functions as a conductor

Ohm's Law states that

<em>The potential difference is proportional to the electric current as long as the resistance is constant</em>

\displaystyle I=\frac{V}{R}\\\\V=I\times R

A simple electrical circuit consists of a voltage source (battery) and a lamp

Ampermeters to measure the strength of the current, must be installed in series with the load to be measured

By changing the voltage source, with constant resistance from a conductor, different current measurements will be obtained. The greater the voltage, the greater the resulting current.

<h3>Learn more</h3>

electrons flow through the device

brainly.com/question/4438943

Keywords : basic electric circuits, Ohm’s law, experiment

5 0
2 years ago
Read 2 more answers
A cart is driven by a large propeller or fan, which can accelerate or decelerate the cart. The cart starts out at the position x
mash [69]

Answer:

The acceleration of the cart is 1.0 m\s^2 in the negative direction.

Explanation:

Using the equation of motion:

Vf^2 = Vi^2 + 2*a*x

2*a*x = Vf^2 - Vi^2

a = (Vf^2 - Vi^2)/ 2*x

Where Vf is the final velocity of the cart, Vi is the initial velocity of the cart, a the acceleration of the cart and x the displacement of the cart.

Let x = Xf -Xi

Where Xf is the final position of the cart and Xi the initial position of the cart.

x = 12.5 - 0

x = 12.5

The cart comes to a stop before changing direction

Vf = 0 m/s

a = (0^2 - 5^2)/ 2*12.5

a = - 1 m/s^2

The cart is decelerating

Therefore the acceleration of the cart is 1.0 m\s^2 in the negative direction.

5 0
2 years ago
An airliner of mass 1.70×105kg1.70×105kg lands at a speed of 75.0 m/sm/s. As it travels along the runway, the combined effects o
Karo-lina-s [1.5K]

Answer:

The airliner travels 1.65 km along the runway before coming to a halt.

Explanation:

Given

Resistive forces = (2.90 × 10⁵) N = 290000 N

Mass of the airliner = (1.70 × 10⁵) kg = 170000 kg

Velocity of airliner = 75 m/s

Let the distance over moved by the airliner be equal to d

According to the work-energy theorem, the work done by the resistive forces in stopping the airliner is equal to the travelling kinetic energy of the airliner.

Work done by the resistive forces = (290000) × d = (290,000d) J

Kinetic energy of the airliner = (1/2)(170000)(75²) = 478,125,000 J

290000d = 478,125,000

d = (478,125,000/290,000)

d = 1648.7 m = 1.65 km

Hope this helps!!!

4 0
2 years ago
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