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nikdorinn [45]
1 year ago
6

A resistor R1 is wired to a battery, then resistor R2 is added in series. Are (a) the potential difference across R1 and (b) the

current i1 through R1 now more than, less than, or the same as previously? (c) Is the equivalent resistance R12 of R1 and R2 more than, less than, or equal to R1?
Physics
1 answer:
tia_tia [17]1 year ago
6 0

Answer:

Explanation:

a ) Earlier emf of cell applied on R₁ but now emf will be distributed among R₁ and R₂

Potential difference on R₁ will become less .

b ) Current is inversely proportional to resistance of the circuit. As resistance increases , current will be less . So current through R₁ will become less.

c )

When resistance is added in series , they are added up to obtain equivalent resistance . So equivalent resistance R₁₂ will be more than R₁ OR R₂.

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For sprinters running at 12 m/s around a curved track of radius 26 m, how much greater (as a percentage) is the average total fo
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Answer:

114.86%

Explanation:

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When running in a circle, there is an additional centripetal force:

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F² = Fx² + Fy²

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F² = m² ((v²/r)² + g²)

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Compared to just the vertical force:

F / Fy

m √((v²/r)² + g²) / mg

√((v²/r)² + g²) / g

Given v = 12 m/s, r = 26 m, and g = 9.8 m/s²:

√((12²/26)² + 9.8²) / 9.8

1.1486

The force is about 114.86% greater (round as needed).

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A person on a cruise ship is doing laps on the promenade deck. on one portion of the track the person is moving north with a spe
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The resultant motion is given by pithagoras, since the two components (north and east) are perpendicular to each other.
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<span>. . . then : </span>

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<span>b/ What is the wavelength of this light ? </span>
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We can solve the problem by using the law of conservation of energy.

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