Answer:
3.73994
No,
Explanation:
= Pressure at the bottom of the lake = 3.5 atm
= Pressure at the top of the lake = 1 atm
= Volume at the bottom of the lake
= Volume at the top of the lake
= Temperature at the bottom of the lake = 4 °C
= Temperature at the top of the lake = 23 °C
From ideal gas law we have the relation
The ratio is 3.73994
As Jacques is ascending if he holds his breath his lungs acting like a bubble would expand. Hence, it is not safe to hold his breath while ascending,
Answer:
Explanation:
a ) At constant pressure , work done = P x Δ V
= 200 x 10³ x ( .1 - .04 )
= 12 x 10³ J .
b )
At constant temperature work done
= n RT ln v₂ / v₁
= PV ln v₂ / v₁
= 200 x 10³ x .04 ln .1 / .04
8 x 10³ x .916
= 7.33 x 10³ J .
Newton's third law says:
"<span>For every action, there is an equal and opposite reaction. ".
So, the force that Tom does on the sister is equal to force the sister applies on Tom:
</span>

<span>where the label "t" means "on Tom", while the label "s" means "on the sister".
From Newton's second law, we also know
</span>

where m is the mass and a the acceleration. <span>so we can rewrite the first equation as
</span>

<span>And find Tom's acceleration:
</span>

<span>
</span>
Answer:
292796435 seconds ≈ 300 million seconds
Explanation:
First of all, the speed of the car is 121km/h = 33.6111 m/s
The radius of the planet is given to be 7380 km = 7380000 m
From the relationship between linear velocity and angular velocity i.e., v=rw, the angular velocity of the car will be w=v/r = 33.6111/7380000 = 0.000000455 rad/s = 4.55 x 10⁻⁶ rad/sec
If the angular velocity of the vehicle about the planet's center is 9.78 times as large as the angular velocity of the planet then we have
w(vehicle) = 9.78 x w(planet)
w(planet) = w(vehicle)/9.78 = 4.55 x 10⁻⁶ / 9.78 = 4.66 x 10⁻⁷ rad/sec
To find the period of the planet's rotation; we use the equation
w(planet) = 2π÷T
Where w(planet) is the angular velocity of the planet and T is the period
From the equation T = 2π÷w = 2×(22/7) ÷ 4.66 x 10⁻⁷ = 292796435 seconds
Therefore the period of the planet's motion is 292796435 seconds which is approximately 300, 000, 000 (300 million) seconds