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IrinaK [193]
1 year ago
9

Which of the following statements about comets is true? A. Comets rarely fall into an orbit around the Sun. They usually enter t

he inner solar system only once and then are gone forever. B. Most comets have a circular orbit that keeps them in the space between Mars and Jupiter. C. Comets have very elliptical orbits that usually take them far beyond the orbit of Pluto, but also take them closer to the Sun than Earth. D. Comets have very elliptical orbits that usually take them closer to the Sun than Earth, but rarely do they get further away than Pluto.
Physics
2 answers:
Lelechka [254]1 year ago
7 0

the correct answer is C

GREYUIT [131]1 year ago
4 0
<h2>Right answer: Comets have very elliptical orbits that usually take them far beyond the orbit of Pluto, but also take them closer to the Sun than Earth</h2>

Comets are celestial bodies constituted by ice, dust and rocks that orbit around the Sun, after having been altered by the Oort cloud; following different trajectories that can be <u>highly eccentric elliptical</u><u> </u>(periodic trajectories), parabolic or hyperbolic.

One of the main characteristics of a comet is that it travels quite fast, on its way around the Sun and has a long tail. It should be noted that the tails of comets always go in the opposite direction to the Sun (due to the radiation pressure of sunlight).

Therefore, the correct option is C.

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A box of books with mass 58 kg rests on the level floor of the campus bookstore. The floor is freshly waxed and has negligible f
Mkey [24]

Answer:

the magnitude of the acceleration a = 0.43 m/s²

Explanation:

m = 58kg

F = 25 N

a = ?

recall that F = ma

=> a = F/m

a = 25/58

a = 0.43 m/s²

3 0
1 year ago
A tennis ball bounces on the floor three times. If each time it loses 22.0% of its energy due to heating, how high does it rise
lesya692 [45]

Answer:

H = 109.14 cm

Explanation:

given,                                                            

Assume ,                                                            

Total energy be equal to 1 unit                                

Balance of energy after first collision = 0.78 x 1 unit

                                                             = 0.78 unit

Balance after second collision = 0.78 ^2 unit

                                                   = 0.6084 unit

Balance after third collision = 0.78 ^3 unit

                                              = 0.475 unit

height achieved by the third collision will be equal to energy remained                                        

H be the height achieved after 3 collision

0.475 ( m g h) = m g H                  

H = 0.475 x h                                    

H = 0.475 x 2.3 m                          

H = 1.0914 m                      

H = 109.14 cm                      

6 0
1 year ago
The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou
bekas [8.4K]

Answer:

2.2 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Converting mph to m/s

29\ mph=29\times 0.44704=12.96\ m/s

58\ mph=58\times 0.44704=25.93\ m/s

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{12.96-0}{1.1}\\\Rightarrow a=11.78\ m/s^2

Considering this acceleration to be constant

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{25.93-0}{11.78}\\\Rightarrow t=2.20\ s

Time it would take to go from zero to 58.0 mph is 2.2 seconds

6 0
2 years ago
A 2.0 g metal cube and a 4.0 g metal cube are 6.0 cm apart, measured between their centers, on a horizontal surface. For both, t
emmasim [6.3K]

Answer:

a) t=10.2s

b) The 2g-cube moves first

Explanation:

Since the electric force is the same on both cubes and so is the coefficient of static friction, the first one to move will be the one with less mass.

So, on the 2g-cube the sum of forces are:

\left \{ {{Ff-Fe=0} \atop {N-m*g=0}} \right.

Replacing the friction on the first equation:

\mu*m*g-Fe=0  Thus   Fe=\mu*m*g=12.74*10^{-3}N

The electric force is:

Fe = \frac{K*q^2}{d^2}  Solving for q:

q=71.44nC

This amount divided by the rate at which they are being charged:

t = 71.44nC / 7nC/s = 10.2s

7 0
1 year ago
A steel rod with a length of l = 1.55 m and a cross section of A = 4.45 cm2 is held fixed at the end points of the rod. What is
Blababa [14]

To solve this problem it is necessary to apply the concepts related to thermal stress. Said stress is defined as the amount of deformation caused by the change in temperature, based on the parameters of the coefficient of thermal expansion of the material, Young's module and the Area or area of the area.

F = AY\alpha \Delta T

Where

A = Cross-sectional Area

Y = Young's modulus

\alpha= Coefficient of linear expansion for steel

\Delta T= Temperature Raise

Our values are given as,

A = 4.45cm^2

T = 37K

\alpha = 1.17*10^{-5}K^{-1}

Y = 200*10^9Gpa

Replacing we have,

F = (4.45*10^{-4})(200*10^9)(1.17*10^{-5})(37)

F = 38526.1N

Therefore the size of the force developing inside the steel rod when its temperature is raised by 37K is 38526.1N

7 0
2 years ago
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