Answer:
= 829.69 Watt
≅ 830 Watt
Explanation:
Given that,
Velocity of air flow = 12.5m/s
Rate of flow of air = 9m³/s
Density of air = 1.18kg/m³
power by kinetic energy = 1/2(mv²)
mass = density × volume
m = 1.18 × 9
= 10.62 kg/s
power = 1/2 mV²
= 1/2 (10.62 × 12.5²)
= 829.69 Watt
≅ 830 Watt
Flow rate
u
=
9
m
3
/
s
Velocity of the air
V
=
8
m/s
Density of the air
ρ
=
1.18
kg
/
m
3
E = ½KA^2 is the mechanical energy of any oscillator. It is the sum of elastic potential energy and
kinetic energy. When amplitude A
decreases by 3%, then
(E2-E1)/E1 = {½K(A2^2/A1^2) }/ ½K(A1^2)
= {(A2^2 – A1^2) / (A1^2)}
= 97^2 – 100^2/100^2
= 5.91% of the mechanical energy is lost each cycle.
Answer:
0.00001266 m
Explanation:
D = Distance from source to screen
m = Order
d = Slit separation
The distance from a point on the screen to the center line

At m = 0


At m = 1

The slit separation is 0.00001266 m
Answer:
The acceleration of the rocket is 10 m/s².
Explanation:
Let the acceleration of the rocket be
m/s².
Given:
Mass of the rocket is, 
Thrust force acting upward is, 
Acceleration due to gravity is, 
Now, force acting in the downward direction is due to the weight of the rocket and is given as:

Now, net force acting on the rocket in upward direction is given as:

Therefore, from Newton's second law, net force acting on the rocket is equal to the product of mass and acceleration.

Therefore, the acceleration of the rocket is 10 m/s².
The answer is:
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"sensors"
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"<span>Monitoring systems may also use ___<u>sensors</u>___, which are devices that respond to a stimulus (such as heat, light, or pressure) and generate an electrical signal that can be measured or interpreted."
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