Would presume the energy as kinetic energy.
E = (1/2)*mv²
But m = 0.05kg, velocity here = 0.70c, where c is the speed of light ≈ 3* 10⁸ m/s
Ke = (1/2)*mv² = 0.5*0.05*(0.7*<span>3* 10⁸)</span>² = 1.1025 * 10¹⁵ Joules
There is no exact match from the options.
Answer:
The concept of conservation of momentum is applied in the particular case of collisions.
The general equation ig given by,

Where,

The crash occurs at an intersection so we must separate the two speeds by their respective vector: x, y.
In the case of the X axis, we have that the body
has a speed = 0, this because it is not the direction in which it travels, therefore

The same analysis must be given for the particular case in the Y direction, where the mass body
does not act with its velocity here, therefore:

We have the two components of a velocity vector given by

Get the magnitude,


With a direction given by

Answer:
2.13 s
Explanation:
Hi!
At t = 0s the rocket is at rest in its platform, so the intial speed is zero. I f the acceleration is A, then the height Y, and the speed V are:


We nedd to find time T during which the rocket engine provides upward acceleration. We know that:

With these 2 equations we can find A and T (dropping units for simplicity):

This involves shooting electrons (from an accelerator) at a target or protons. This technique provided evidence for the existence of quarks. <span>proton-antiproton scattering as well.
</span>hope this helps
Answer:
1.38*10^18 kg
Explanation:
According to the Newton's law of universal gravitation:

where:
G= Gravitational constant (6.674×10−11 N · (m/kg)2)
ma= mass of the astronaut
mp= mass of the planet

so:
