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schepotkina [342]
1 year ago
9

You travel in a circle, whose circumference is 8 kilometers, at an average speed of 8 kilometers/hour. If you stop at the same p

oint you started from, what is your average velocity? 0 kilometers/hour 2 kilometers/hour 4 kilometers/hour 8 kilometers/hour 16 kilometers/hour
Physics
2 answers:
ehidna [41]1 year ago
7 0
Velocity = (displacement) / (time)

Displacement = straight-line distance between start-point and end-point

If you stop at the same point you started from, then
your displacement for the trip is zero, and your average
velocity is also zero.

Schach [20]1 year ago
5 0
Velocity = (displacement) / (time)

Displacement = straight-line distance between start-point and end-point

If you stop at the same point you started from, then
your displacement for the trip is zero, and your average
velocity is also zero.

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The total energy of a 0.050 kg object travelling at 0.70 c is
quester [9]
Would presume the energy as kinetic energy.

E = (1/2)*mv²

But m = 0.05kg, velocity here = 0.70c, where c is the speed of light ≈ 3* 10⁸ m/s

Ke =  (1/2)*mv² = 0.5*0.05*(0.7*<span>3* 10⁸)</span>² = 1.1025 * 10¹⁵ Joules


There is no exact match from the options.
4 0
1 year ago
A Honda Civic and an 18 wheeler approach a right angle intersection and then collide. After the collision, they become interlock
Goryan [66]

Answer:

The concept of conservation of momentum is applied in the particular case of collisions.  

The general equation ig given by,

M_1V_1 + M_2V_2 = (M_1+M_2) * V_f,

Where,

M_2 = 4 M_1

The crash occurs at an intersection so we must separate the two speeds by their respective vector: x, y.

In the case of the X axis, we have that the body M_2 has a speed = 0, this because it is not the direction in which it travels, therefore

M_1* 13 = (M_1+M_2) * V_{fx} \\M_1*13 = (M_1+4M_1)*V_{fx}\\M_1*13=5M_1*V_{fx}\\Vx = \frac{13}{5}m/s

The same analysis must be given for the particular case in the Y direction, where the mass body M_1 does not act with its velocity here, therefore:

M_2* 13 = (M_1+M_2) * V_{fy},\\4*M_1* 13 = 5Ma * V_{fy} ,\\V_{fy} = \frac{52}{5}m/s ,

We have the two components of a velocity vector given by V_f = \frac{13}{5}\hat{i} + \frac{52}{5}\hat{j}

Get the magnitude,

V_f = \sqrt{(\frac{13}{5})^2+(\frac{52}{5})^2}

V_f = 10.72 m/s

With a direction given by

Tan^{-1} \frac{4}{1} = 75.96 \°

8 0
2 years ago
A toy rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward a
Dvinal [7]

Answer:

2.13 s

Explanation:

Hi!

At t = 0s the rocket is at rest in its platform, so the intial speed is zero. I f the acceleration is A, then the height Y, and the speed V are:

Y=\frac{A}{2}t^2

V=At

We nedd to find time T during  which the rocket engine provides upward acceleration. We know that:

64\;m=\frac{A}{2}T^2\\ 60\frac{m}{s} =AT\\

With these 2 equations we can find A and T (dropping units for simplicity):

A=\frac{60}{T} \\64 =\frac{30}{T} T^2=30T\\T=\frac{64}{30}\approx 2.13\;s

4 0
2 years ago
What is the speed of each neutron as they crash together? keep in mind that both neutrons are moving?
Sophie [7]
This involves shooting electrons (from an accelerator) at a target or protons. This technique provided evidence for the existence of quarks. <span>proton-antiproton scattering as well.
</span>hope this helps
7 0
1 year ago
Read 2 more answers
An astronaut exploring a distant solar system lands on an unnamed planet with a radius of 2530 km. When the astronaut jumps upwa
Natali [406]

Answer:

1.38*10^18 kg

Explanation:

According to the Newton's law of universal gravitation:

F=G*\frac{m_a*m_p}{r^2}

where:

G= Gravitational constant (6.674×10−11 N · (m/kg)2)

ma= mass of the astronaut

mp= mass of the planet

F=m_a.a\\(v_f )^2=(v_o)^2+2.a.\Delta y\\\\a=\frac{(v_f)^2-(v_o)^2}{2.\Delta y}\\\\a=\frac{(0)^2-(4.29m/s)^2}{2.0.64m}=14.38m/s^2\\\\F=m_a*14.38m/s^2

so:

m_a*14.38m/s^2=(6.674*10^{-11}N.(m/kg)^2)*\frac{m_a.m_p}{(2.530*10^3m)^2}\\m_p=\frac{14.38m/s^2(2.530*10^3m)^2}{(6.674*10^{-11}N.(m/kg)^2)}\\\\m_p=1.38*10^{18}kg

7 0
2 years ago
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