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shtirl [24]
1 year ago
7

What is the total energy released when 9.11 x10^-31 ki?

Physics
1 answer:
77julia77 [94]1 year ago
4 0
Cola because its tasty hahahahahahahahgahhahahahahhahahahhahhahhahahaaha
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Two students, sitting on frictionless carts, push against each other. Both are initially at rest and the mass of student 1 and t
Zepler [3.9K]

Answer:

  v₂ = v/1.5= 0.667 v

Explanation:

For this exercise we will use the conservation of the moment, for this we will define a system formed by the two students and the cars, for this isolated system the forces during the contact are internal, therefore the moment conserves.

Initial moment before pushing

    p₀ = 0

Final moment after they have been pushed

    p_{f} = m₁ v₁ + m₂ v₂

   p₀ =  p_{f}

   0 = m₁ v₁ + m₂ v₂

   m₁ v₁ = - m₂ v₂

Let's replace

   M (-v) = -1.5M v₂

   v₂ = v / 1.5

  v₂ = 0.667 v

6 0
1 year ago
A What CE describes the way energy is stored in a sandwich​
SVETLANKA909090 [29]
What is Potential Energy? You probably already know that without eating, your body becomes weak from lack of energy. Take a few bites of a turkey sandwich, and moments later, you feel much better. That's because food molecules contain potential energy, or stored energy, that can do work in the future. Hope it helps
8 0
2 years ago
a catcher picks up a baseball from the ground, if the unbalanced force on the ball is 7.25 x 10^-2 N and 4.35 x 10^-2 J of work
omeli [17]
<span>The work is being done against gravity, and equals (Force * vertical distance).
A Joule of work is equivalent to 1 Newton-metre

So vertical distance d = work done / Force
d = 4.35*10^-2J / 7.25*10^-2 N = 0.6 m = 60cm = 600mm </span>
6 0
2 years ago
"A hole is punched in a full milk carton, 10 cm below the top. What is the initial velocity of outflow?"
lesya692 [45]
P 1 = 101,325 Pa (atmospheric pressure)
Milk has almost same density as water: (Rho)= 1,000 kg /m³ 
P 2 = 101,325 Pa + 1,000 kg/m³ · 9.81 m/s² · 0.1 m = 102,306 Pa
The hydrostatic equation:
P 1 + (Rho)v1² / 2 = P 2 + (Rho)·g·h2
101,325 + 1,000 v1²/2  = 102,306 + 1000 · 9.81 · 0.1
500 v 1² = 102,306 + 981 - 101,325
v 1² = 3.924
v 1 = √ 3.924
v 1 = 1.98 m/s
The initial velocity of outflow is 1.98 m/s.

8 0
2 years ago
Read 2 more answers
Calculate the speed of the car at each checkpoint by dividing the distance between each checkpoint, in meters, by the change in
Ivenika [448]

Answer:

1.09

1.95

2.37

2.80

Explanation:

just did it

8 0
1 year ago
Read 2 more answers
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