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2 years ago

Which of the following use the same units of measurement?

Physics

2 answers:

o-na [289]2 years ago

8 0

Meters, metric, body mass index.

Afina-wow [57]2 years ago

7 0

Metric
meters
body mass index

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A physics student with a stopwatch drops a rock into a very deep well, and measures the time between when he drops the rocks and

tankabanditka [31]

Answer:

h= 161.06 m

Explanation:

Given that

Speed of the sound ,C= 343 m/s

Total time ,t= 6.2 s

lets take the depth of the well = h

The time taken by stone before striking the water = t₁

we know that

$h=\dfrac{1}{2}gt_1^2$

$t_1=\sqrt{\dfrac{2h}{g}}$

The time taken by sound =t₂

$t_2=\dfrac{h}{343}$

The total time

t = t₁+ t₂

$6.2 = \sqrt{\dfrac{2h}{g}}+\dfrac{h}{343}$

$6.2 = \sqrt{\dfrac{2h}{9.81}}+\dfrac{h}{343}$

Now by solving the above equation we get

h= 161.06 m

Therefore the depth of the well will be 161.06 m.

6 0

2 years ago

A particle in the first excited state of a one-dimensional infinite potential energy well (with U = 0 inside the well) has an en

nataly862011 [7]

Answer:

The energy of this particle in the ground state is E₁=1.5 eV.

Explanation:

The energy $E_{n}$ of a particle of mass m in the nth energy state of an infinite square well potential with width L is:

$E_{n}=\frac{n^{2}h^{2}}{8mL^{2}}$

In the ground state (n=1). In the first excited state (n=2) we are told the energy is E₂= 6.0 eV. If we replace in the above equation we get that:

$E_{1}=\frac{h^{2}}{8mL^{2}}$

$E_{2}=\frac{h^{2}}{2mL^{2}}$

So we can rewrite the energy in the ground state as:

$E_{1}=\frac{1}{4}(\frac{h^{2}}{2mL^{2}})$

$E_{1}=\frac{1}{4} E_{2}$

$E_{1}=\frac{1}{4} ( 6.0\ eV)$

Finally

$E_{1}=1.5\ eV$

6 0

2 years ago

You stand on a bathroom scale in a moving elevator. what happens to the scale reading if the cable holding the elevator suddenly

Viefleur [7K]

A bathroom scales works due to gravity. Under normal conditions, a reading can be obtained when your body is pushing some force on the scale. However in this case, since you and the scale are both moving downwards, so your body is no longer pushing on the scale. Therefore the answer is:

The reading will drop to 0 instantly

7 0

2 years ago

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Physics in motion unit 6a the nature of waves

mylen [45]

What’s the question?

7 0

2 years ago

Assume that you stay on the earth's surface. what is the ratio of the sun's gravitational force on you to the earth's gravitatio

Pachacha [2.7K]

First, let's determine the gravitational force of the Earth exerted on you. Suppose your weight is about 60 kg.

F = Gm₁m₂/d²
where
m₁ = 5.972×10²⁴ kg (mass of earth)
m₂ = 60 kg
d = 6,371,000 m (radius of Earth)
G = 6.67408 × 10⁻¹¹ m³ kg⁻¹ s⁻²

F = ( 6.67408 × 10⁻¹¹ m³ kg⁻¹ s⁻²)(60 kg)(5.972×10²⁴ kg)/(6,371,000 m )²
F = 589.18 N

Next, we find the gravitational force exerted by the Sun by replacing,
m₁ = 1.989 × 10³⁰ kg
Distance between centers of sun and earth = 149.6×10⁹ m
Thus,
d = 149.6×10⁹ m - 6,371,000 m = 1.496×10¹¹ m

Thus,
F = ( 6.67408 × 10⁻¹¹ m³ kg⁻¹ s⁻²)(60 kg)(1.989 × 10³⁰ kg)/(1.496×10¹¹ m)²
F = 0.356 N

Ratio = 0.356 N/589.18 N
Ratio = 6.04

5 0

2 years ago

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