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Rama09 [41]
2 years ago
15

Assertion(A):The distance moved by an object in unit time is called its speed. Reason (R):Faster vehicles have higher speeds. i)

A is correct while R is incorrect. ii) R is correct while A is incorrect. iii) Both A and R are correct iv) Both A and R are incorrect.
Physics
1 answer:
ikadub [295]2 years ago
8 0

Answer:

it's ii) R is correct while A is incorrect

Explanation:

cuz, both statements are correct but the reason is not the correct reason for the assertion,

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DESPERATEA rocket of mass 40 000 kg takes off and flies to a height of 2.5 km as its engines produce 500 000 N of thrust.
77julia77 [94]

Answer:

i=1250000000Nm

ii=50000m/s

Explanation:

energy=force ×distance

500000N×(2.5×1000)m

=1250000000Nm

ii. Force=mass ×acceleration

500000N =40000kg ×a

500000 ÷40000=12.5a

s=1/2at^2

2500m=1/2×12.5×t^2

2500m=6.25×t^s

2500÷6.25=400

t^2=400

√t^2=√400

t=20seconds

speed=distance ×time taken

=2500m × 20s

=50000m/s

5 0
2 years ago
A rectangular block weighs 240 N. the area of the block in contact with the floor is 20 cm2.calculate the pressure on the floor(
maks197457 [2]

Answer:

12 N/cm²

Explanation:

From the question given above, the following data were obtained:

Weight (W) of block = 240 N

Area (A) = 20 cm²

Pressure (P) =?

Next, we shall determine the force exerted by the block. This can be obtained as follow:

Weight (W) of block = 240 N

Force (F) =.?

Weight and force has the same unit of measurement. Thus, we force applied is equivalent to the weight of the block. Thus,

Force (F) = Weight (W) of block = 240 N

Force (F) = 240 N

Finally, we shall determine the pressure on the floor as follow:

Force (F) = 240 N

Area (A) = 20 cm²

Pressure (P) =?

P = F/A

P = 240 / 20

P = 12 N/cm²

Therefore, the pressure on the floor is 12 N/cm².

7 0
1 year ago
Keisha told her friend that she can get to the town library by walking one mile east, turning left, and then walking a half a mi
Mama L [17]

The best improvement to these instructions that Keisha can make
immediately and easily is to describe where the instructions start from. 

Does the route start from Keisha's house ?  From her friend's house ? 
From my house ? 

Knowledge of the coordinate reference frame makes a big difference,
and it's essential.

7 0
2 years ago
Read 2 more answers
To determine the height of a flagpole, Abby throws a ball straight up and times it. She sees that the ball goes by the top of th
Kryger [21]

Answer:

H = 10.05 m

Explanation:

If the stone will reach the top position of flag pole at t = 0.5 s and t = 4.1 s

so here the total time of the motion above the top point of pole is given as

\Delta t = 4.1 - 0.5 = 3.6 s

now we have

\Delta t = \frac{2v}{g}

3.6 = \frac{2v}{9.8}

v = 17.64 m/s

so this is the speed at the top of flag pole

now we have

v_f - v_i = at

17.64 - v_i = (-9.8)(0.5)

v_i = 22.5 m/s

now the height of flag pole is given as

H = \frac{v_f + v_i}{2}t

H = \frac{22.5 + 17.64}{2} (0.5)

H = 10.05 m

5 0
1 year ago
A student evaluates a weight loss program by calculating the number of times he would need to climb a 14.0 m high flight of step
Liula [17]

Answer:

400 trips

Explanation:

Mechanical energy needed to climb 14 m by a man of 68 kg

= mgh

= 68 x 9.8 x 14

= 9330 J

1 Kg of fat releases 3.77 x 10⁷ J of energy

.45 kg of fat releases 1.6965 x 10⁷ J of energy

22% is converted into mechanical energy

so 22% of 1.6965 x 10⁷ J

= 3732.3 x 10³ J of mechanical energy will be available for mechanical work.

one trip of climbing of 14 m requires 9330 J of mechanical energy

no of such trip possible with given mechanical energy

= 3732.3 x 10³ / 9330

= 400 trips

7 0
2 years ago
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