Answer:
i=1250000000Nm
ii=50000m/s
Explanation:
energy=force ×distance
500000N×(2.5×1000)m
=1250000000Nm
ii. Force=mass ×acceleration
500000N =40000kg ×a
500000 ÷40000=12.5a
s=1/2at^2
2500m=1/2×12.5×t^2
2500m=6.25×t^s
2500÷6.25=400
t^2=400
√t^2=√400
t=20seconds
speed=distance ×time taken
=2500m × 20s
=50000m/s
Answer:
12 N/cm²
Explanation:
From the question given above, the following data were obtained:
Weight (W) of block = 240 N
Area (A) = 20 cm²
Pressure (P) =?
Next, we shall determine the force exerted by the block. This can be obtained as follow:
Weight (W) of block = 240 N
Force (F) =.?
Weight and force has the same unit of measurement. Thus, we force applied is equivalent to the weight of the block. Thus,
Force (F) = Weight (W) of block = 240 N
Force (F) = 240 N
Finally, we shall determine the pressure on the floor as follow:
Force (F) = 240 N
Area (A) = 20 cm²
Pressure (P) =?
P = F/A
P = 240 / 20
P = 12 N/cm²
Therefore, the pressure on the floor is 12 N/cm².
The best improvement to these instructions that Keisha can make
immediately and easily is to describe where the instructions start from.
Does the route start from Keisha's house ? From her friend's house ?
From my house ?
Knowledge of the coordinate reference frame makes a big difference,
and it's essential.
Answer:

Explanation:
If the stone will reach the top position of flag pole at t = 0.5 s and t = 4.1 s
so here the total time of the motion above the top point of pole is given as

now we have



so this is the speed at the top of flag pole
now we have



now the height of flag pole is given as



Answer:
400 trips
Explanation:
Mechanical energy needed to climb 14 m by a man of 68 kg
= mgh
= 68 x 9.8 x 14
= 9330 J
1 Kg of fat releases 3.77 x 10⁷ J of energy
.45 kg of fat releases 1.6965 x 10⁷ J of energy
22% is converted into mechanical energy
so 22% of 1.6965 x 10⁷ J
= 3732.3 x 10³ J of mechanical energy will be available for mechanical work.
one trip of climbing of 14 m requires 9330 J of mechanical energy
no of such trip possible with given mechanical energy
= 3732.3 x 10³ / 9330
= 400 trips