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Rama09 [41]
2 years ago
15

Assertion(A):The distance moved by an object in unit time is called its speed. Reason (R):Faster vehicles have higher speeds. i)

A is correct while R is incorrect. ii) R is correct while A is incorrect. iii) Both A and R are correct iv) Both A and R are incorrect.
Physics
1 answer:
ikadub [295]2 years ago
8 0

Answer:

it's ii) R is correct while A is incorrect

Explanation:

cuz, both statements are correct but the reason is not the correct reason for the assertion,

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A physics department has a Foucault pendulum, a long-period pendulum suspended from the ceiling. The pendulum has an electric ci
antoniya [11.8K]

Answer:

t=37 mins -> 2220sec

We want "T" which is the pendulum time constant

Using this equation

.5A=Ae^(-t/T)

The .5A is half the amplitude

Take ln of both sides to get ride of Ae

=ln(.5)=-2220/T

Now rearrange to = T

T=-2220/ln(.5) = 3202.78sec / 60 secs = 53.38 mins -> first part of the answer.

The second part is really easy. It took 37 mins to decay half way. meaning to decay another half of 50% which equals 25% it will take an additional 37 mins!

8 0
2 years ago
In springboard diving, the diver strides out to the end of the board, takes a jump onto its end, and uses the resultant spring-l
Ksenya-84 [330]

Answer:

10.4 m/s

Explanation:

The problem can be solved by using the following SUVAT equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

For the diver in the problem, we have:

u=+6.3 m/s is the initial velocity (positive because it is upward)

a=g=-9.8 m/s^2 is the acceleration of gravity (negative because it is downward)

By substituting t = 1.7 s, we find the velocity when the diver reaches the water:

v=+6.3 + (-9.8)(1.7)=-10.4 m/s

And the negative sign means that the direction is downward: so, the speed is 10.4 m/s.

3 0
2 years ago
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Large and small numbers are often best entered in exponential notation. For example, the mass of the earth is 5.98x1024 kg and t
Doss [256]

Answer:

The charge to mass ratio is -1.76\times10^{11}

Explanation:

Mass\ of\ electron=m_e=9.11\times10^{-31} kg\\ Charge\ of\ the\ electron=q_e=-1.60\times10^{-19} C\\

We need to find how much charge is contained  in the electron per unit of mass, to do this we divide the charge in an electron and the mass of an electron:

\frac{Charge\ of\ electron}{Mass\ of\ electron}=\frac{q_e}{m_e}\frac{C}{kg}=\frac{-1.60\times10^{-19} C}{9.11\times10^{-31} kg}=-1.76\times10^{11} \frac{C}{kg}

4 0
2 years ago
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An electron and a proton, starting from rest, are accelerated through an electric potential difference of the same magnitude. in
Yakvenalex [24]
The charges are the same in absolute value, so the change of potential energy is the same. That means that the change in kinetic energy is also the same. Then:

1 = Ke/Kp = m_e *v_e^2 / m_p * v_p^2, or

v_e/v_p = sqrt( m_p/m_e),

So the speed of the electron will be sqrt( m_p/m_e) times greater than the speed of the proton
4 0
2 years ago
A 0.20-kg object attached to the end of a string swings in a vertical circle (radius = 80 cm). at the top of the circle the spee
gayaneshka [121]

Answer:

Tension in the string at this position: 3.1 N.

Explanation:

Convert the radius of the circle to meters:

r = 80\;\text{cm} = 0.80\;\text{m}.

What's the net force on the object?

The object is in a circular motion. As a result,

\displaystyle \Sigma F = \frac{m\cdot v^{2}}{r},

where

  • \Sigma F is the net force on the object,
  • m is the mass of the object,
  • v is the velocity of the object, and
  • r is the radius of the circular motion.

For this object,

\displaystyle \Sigma F = \frac{0.20\times {4.5}^{2}}{0.80} = 5.0625\;\text{N}.

The output unit of net force should be standard if the unit for mass, velocity, and radius are all standard. The net force shall always point towards the center. In this case the net force points downwards.

What are the forces on this object?

There are two forces on the object at this moment:

  • Weight, W, which points downwards. W = m\cdot g = 0.20\times 9.81 = 1.962\;\text{N}.
  • Tension, T, which also points downwards. The size of the tension force needs to be found.

What's the size of the tension force?

Gravity and tension points in the same direction. The size of their resultant force is the sum of the two forces. In other words,

\Sigma F = T + W.

T = \Sigma F - W = 5.0625 - 1.962 = 3.1.

All three values in this question are given with two sig. fig. Round the value of T to the same number of significant figures.

4 0
2 years ago
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