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Sunny_sXe [5.5K]
2 years ago
14

Keisha told her friend that she can get to the town library by walking one mile east, turning left, and then walking a half a mi

le north.
Which best describes how Keisha can improve these instructions to better help her friend find the library?
Physics
2 answers:
Mama L [17]2 years ago
7 0

The best improvement to these instructions that Keisha can make
immediately and easily is to describe where the instructions start from. 

Does the route start from Keisha's house ?  From her friend's house ? 
From my house ? 

Knowledge of the coordinate reference frame makes a big difference,
and it's essential.

nikitadnepr [17]2 years ago
3 0

Answer;

providing a reference point to follow

Explanation;

A reference point is a starting point you choose to describe the location, or position, of an object.

A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point. A reference point is some point in space used to describe the position of other things, relative to this reference point.

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Find the centripetal force needed by a 1275 kg car to make a turn of radius 40.0 m at a speed of 25.0 km/h
natima [27]
<span>v = 25.0 km/</span><span>h = 25*5/18 m/s = 6.94 m/s

</span><span>centripetal force = mv²/r = 1275*6.94²/40 = 1537.18 N </span>

4 0
2 years ago
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Explain why the coin is able to float on top of the water in this glass
makkiz [27]

Explanation:

Becuse the coin has a <em><u>Lesser</u></em><em><u> </u></em><em><u>Density</u></em> than water.

3 0
1 year ago
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4. A trolley of mass 2kg rests next to a trolley of mass 3 kg on a flat
nydimaria [60]

Answer:

a. The total momentum of the trolleys which are at rest before the separation is zero

b. The total momentum of the trolleys after separation is zero

c. The momentum of the 2 kg trolley after separation is 12 kg·m/s

d. The momentum of the 3 kg trolley is -12 kg·m/s

e. The velocity of the 3 kg trolley = -4 m/s

Explanation:

a. The total momentum of the trolleys which are at rest before the separation is zero

b. By the principle of the conservation of linear momentum, the total momentum of the trolleys after separation = The total momentum of the trolleys before separation = 0

c. The momentum of the 2 kg trolley after separation = Mass × Velocity = 2 kg × 6 m/s = 12 kg·m/s

d. Given that the total momentum of the trolleys after separation is zero, the momentum of the 3 kg trolley is equal and opposite to the momentum of the 2 kg trolley = -12 kg·m/s

e. The momentum of the 3 kg trolley = Mass of the 3 kg Trolley × Velocity of the 3 kg trolley

∴ The momentum of the 3 kg trolley = 3 kg × Velocity of the 3 kg trolley = -12 kg·m/s

The velocity of the 3 kg trolley = -12 kg·m/s/(3 kg) = -4 m/s

3 0
2 years ago
A lightning bolt transfers 6.0 coulombs of charge from a cloud to the ground in 2.0 x 10-3 second. what is the average current d
AlladinOne [14]
The current is defined as the amount of charge transferred through a certain point in a certain time interval:
I= \frac{Q}{\Delta t}
where
I is the current
Q is the charge
\Delta t is the time interval

For the lightning bolt in our problem, Q=6.0 C and \Delta t= 2.0 \cdot 10^{-3}s, so the average current during the event is
I= \frac{Q}{\Delta t} = \frac{6.0 C}{2.0 \cdot 10^{-3} s}=3000 A
4 0
2 years ago
A semi is traveling down the highway at a velocity of v = 26 m/s. The driver observes a wreck ahead, locks his brakes, and begin
Dovator [93]

Answer:

fcosθ + Fbcosθ  =Wtanθ

Explanation:

Consider the diagram shown in attachment

fx= fcosθ (fx: component of friction force in x-direction ; f: frictional force)

Fbx= Fbcosθ ( Fbx: component of braking force in x-direction ; Fb: braking force)

Wx= Wtanθ (Wx: component of weight in x-direction ; W: Weight of semi)

sum of x-direction forces = 0

fx+ Fbx=Wx

fcosθ + Fbcosθ  =Wtanθ

7 0
2 years ago
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