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2 years ago

A batter swings at a baseball. The action force is the bat hitting the ball with a force of 5N. What is the reaction force?

Physics

2 answers:

nlexa [21]2 years ago

7 0

Answer:

The ball hitting the bat.

Explanation:

It is given that, a batter swings at a baseball. When the ball is being hitted by the bat, the action force acting on it is 5 N. Let R is the reaction force. It is equal to the action force but it acts in the opposite direction as per Newton's third law of motion.

The action and reaction forces acts on two different objects. Here, if the action force is " bat hitting the ball" then the reaction force will be "the ball hitting the bat" with a force of -5 N.

Hence, the correct option is (d) "the ball hitting the bat".

omeli [17]2 years ago

6 0

The ball hitting the bat

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A man carries a load of mass 2.6kg from one end of a uniform pole 100cm long which has a mass 0.4kg. The pole rest on his should

miskamm [114]

Answer:

F = 39.2 N (hand force) and N = 68.6 N (shoulder force)

Explanation:

In this exercise we must use the rotational and translational equilibrium conditions, we have several forces: the weight (W) of the pole applied at its geometric center, the load (w1) at one end, the shoulder support (N) 60 cm from the load and hand force (F) at the other end of the pole

Let's set the reference system at the fit point of the shoulder

∑ τ = 0

We will assume that the counterclockwise turns are positive

w₁ 0.60 + W 0.1 + F₁ 0 - F 0.4 = 0

all distances are measured from the support of the man (x₀ = 0.60 m)

F = (w₁ 0.60 + W 0.1) / 0.4

F = (m₁ 0.6 + m 0.1) g / 0.4

let's calculate

F = (2.6 0.6 + 0.4 0.1) 9.8 / 0.4

F = 39.2 N

this is the force that the hand must exert to keep the system in balance

We apply the translational equilibrium condition

-w₁ -W + N - F = 0

N = w₁ + W + F

N = (m₁ + m) g + F

let's calculate

N = (2.6 + 0.4) 9.8 + 39.2

N = 68.6 N

6 0

1 year ago

"What will the pressure inside the container become if the piston is moved to the 1.60 L mark while the temperature of the gas i

asambeis [7]

This question is incomplete, the complete question is;

The Figure shows a container that is sealed at the top by a moveable piston, Inside the container is an ideal gas at 1.00 atm. 20.0°C and 1.00 L.

"What will the pressure inside the container become if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant?"

Answer:

the pressure inside the container become 0.625 atm if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant

Explanation:

Given that;

P₁ = 1.00 atm

P₂ = ?

V₁ = 1 L

V₂ = 1.60 L

the temperature of the gas is kept constant

we know that;

P₁V₁ = P₂V₂

so we substitute

1 × 1 = P₂ × 1.60

P₂ = 1 / 1.60

P₂ = 0.625 atm

Therefore the pressure inside the container become 0.625 atm if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant

5 0

2 years ago

One end of a string is fixed. An object attached to the other end moves on a horizontal plane with uniform circular motion of ra

sveticcg [70]

Answer:

If both the radius and frequency are doubled, then the tension is increased 8 times.

Explanation:

The radial acceleration ( $a_{r}$ ), measured in meters per square second, experimented by the moving end of the string is determined by the following kinematic formula:

$a_{r} = 4\pi^{2}\cdot f^{2}\cdot R$ (1)

Where:

$f$ - Frequency, measured in hertz.

$R$ - Radius of rotation, measured in meters.

From Second Newton's Law, the centripetal acceleration is due to the existence of tension ( $T$ ), measured in newtons, through the string, then we derive the following model:

$\Sigma F = T = m\cdot a_{r}$ (2)

Where $m$ is the mass of the object, measured in kilograms.

By applying (1) in (2), we have the following formula:

$T = 4\pi^{2}\cdot m\cdot f^{2}\cdot R$ (3)

From where we conclude that tension is directly proportional to the radius and the square of frequency. Then, if radius and frequency are doubled, then the ratio between tensions is:

$\frac{T_{2}}{T_{1}} = \left(\frac{f_{2}}{f_{1}} \right)^{2}\cdot \left(\frac{R_{2}}{R_{1}} \right)$ (4)

$\frac{T_{2}}{T_{1}} = 4\cdot 2$

$\frac{T_{2}}{T_{1}} = 8$

If both the radius and frequency are doubled, then the tension is increased 8 times.

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1 year ago

After an incandescent lamp is turned on, the temperature of its filament rapidly increases from room temperature to its operatin

IrinaVladis [17]

Answer: (1) The resistance increases and the current decreases.

Explanation:

When the temperature of the filament increases, the vibrational energy of the constituent atoms increases which leads to increase in inter-atomic collision. Thus, the resistance would increase. The increases in resistance would obstruct the flow of charges more leading to decrease in the value of the current.

Hence, when the temperature of the filament increase, the resistance increases and current decreases.

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