answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fantom [35]
2 years ago
5

Martin is conducting an experiment. His first test gives him a yield of 5.2 grams. His second test gives him a yield of 1.3 gram

s. His third test gives him a yield of 8.5 grams. On average, his yield is 5.0 grams, which is close to the known yield of 5.1 grams of substance. Which of the following are true?
Physics
1 answer:
Bogdan [553]2 years ago
4 0

Complete Question

Martin is conducting an experiment. His first test gives him a yield of 5.2 grams. His second test gives him a yield of 1.3 grams. His third test gives him a yield of 8.5 grams. On average, his yield is 5.0 grams, which is close to the known yield of 5.1 grams of substance. Which of the following are true?

A His results are accurate but not precise.

B His results are neither accurate nor precise.

C His results are both accurate and precise

D His results are precise but not accurate.

Answer:

Correct option is A

Explanation:

From the question we are told that  

   The  yield of the first test k  =  5.2 \  g

   The  yield of the second  is  u =  1.3 \  g

   The  third yield is  p =  8.5 \  g

   The  average yield  A = 5.0 \ g

    The  know yield is  A_S =  5.1 \  g

From the data given we see that

        A_S \ne A

Since his average yield is closer to the known yield then the answer is accurate

But since the yield for each test are not repeated the answer is not precise

So the answer is accurate but not precise  

You might be interested in
An electron is trapped in a square well of unknown width, L. It starts in unknown energy level, n. When it falls to level n-1 it
Lady bird [3.3K]

Answer:

(1) En to n-1 = 0.55 ev

(2) En-1 to n-2 = 0.389 ev

(3) ninitial =4

(4) L =483.676 ×10^-11 nm

(5) λlongest= 1773.33 nm

Explanation:

Detailed explanation of answer is given in the attached files.

4 0
2 years ago
A mass of 0.4 kg hangs motionless from a vertical spring whose length is 0.76 m and whose unstretched length is 0.41 m. Next the
Blizzard [7]
<h3><u>Answer;</u></h3>

= 1.256 m

<h3><u>Explanation;</u></h3>

We can start by finding the spring constant  

F = k*y  

Therefore;  k = F/y = m*g/y

                               = 0.40kg*9.8m/s^2/(0.76 - 0.41)

                               = 11.2 N/m  

Energy is conserved  

Let A be the maximum displacement  

Therefore;  1/2*k*A^2 = 1/2*k*(1.20 - 0.41)^2 + 1/2*m*v^2  

Thus;  A = sqrt((1.20 - 0.55)^2 + m/k*v^2)

               = sqrt((1.20 -0.55)^2 + 0.40/9.8*1.6^2)

                = 0.846 m  

Thus; the length will be 0.41 + 0.846  = 1.256 m

6 0
2 years ago
What force would be needed to accelerate a 0.040-kg golf ball at 20.0 m/s?
Naily [24]

Answer:

any amount of force will do it as time is not mentioned here

5 0
2 years ago
Here are the positions at three different times for a bee in flight (a bee's top speed is about 7 m/s). Time 6.6 s 6.9 s 7.2 s P
Ber [7]

Answer:

(A.) (- 4.33, 6.33 , 0); (B.) (- 3.66, 7.5, 0); (C.) average at (A) (- 4.33, 6.33 , 0) ; (D.) (- 0.2165, 0.3165, 0)

Explanation:

Given the following :

Time - - - - - - - 6.6s - - - - - - - - - 6.9s - - - - - 7.2s

Position - (1.8,5.0,0) - (0.5,6.9,0) - - (−0.4,9.5,0)

(a) Between 6.6 s and 6.9 s, what was the bee's average velocity?

Vavg = Distance / time

[(0.5,6.9,0) - (1.8,5.0,0)] / 6.9 - 6.6

Vavg = [(0.5 - 1.8), (6.9 - 5.0), (0 - 0)] / 0.3

Vavg = - 1.3 / 0.3, 1.9/0.3, 0/3

Vavg = (- 4.33, 6.33 , 0)

b) Between 6.6 s and 7.2 s, what was the bee's average velocity?

Vavg = [(−0.4,9.5,0) - (1.8,5.0,0)] / 7.2 - 6.6

Vavg = - 2. 2/0.6, 4.5/0.6, 0/0.6

Vavg = (- 3.66, 7.5, 0)

c.) Of the two averages (- 4.3, 6.3 , 0) is closer to the instantaneous Velocity at 6.6s

D.) (d) Using the best information available, what was the displacement of the bee during the time interval from 6.6 s to 6.65 s?

Displacement = Velocity * time

Vavg between 6.6 to 6.9 ; time = (6.65 - 6.6) = 0.05 s

= (- 4.33, 6.33 , 0) * 0.05

= (- 0.2165, 0.3165, 0)

5 0
2 years ago
The chart shows data for four moving objects. A 4 column table with 4 rows. The first column is labeled Object with entries, W,
KatRina [158]

Answer:

y

Explanation:

I took the test

3 0
1 year ago
Other questions:
  • Starting from equilibrium at point 0, what point on the pv diagram will describe the ideal gas after the following process? lock
    5·2 answers
  • A 480-kilogram horse runs across a field at a rate of 40 km/hr. What is the magnitude of the horse's momentum?
    12·2 answers
  • If no friction acts on a diver during a dive, then which of the following statements is true? A) The total mechanical energy of
    11·2 answers
  • Describing the motion of an object can be difficult to do and using graphs help make motion easier to understand. Motion is a ch
    15·2 answers
  • A uniformly accelerated car passes three equally spaced traffic signs. The signs are separated by a distance d = 25 m. The car p
    8·1 answer
  • A physics student shoves a 0.50-kg block from the bottom of a frictionless 30.0° inclined plane. The student performs 4.0 j of w
    8·1 answer
  • In a rocket-propulsion problem the mass is variable. Another such problem is a raindrop falling through a cloud of small water d
    13·1 answer
  • At a drag race, a jet car travels 1/4 mile in 5.2 seconds. What is the final speed of the
    15·1 answer
  • A block is projected with speed v across a horizontal surface and slides to a stop due to friction. The same block is then proje
    8·1 answer
  • When 999mm is added to 100m ______ is the result​
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!