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Neko [114]
2 years ago
5

Which of these is true of a chemical reaction? (a) energy is always transferred from reactants to products. (b) Energy is transf

erred between products and reactants. (c) Energy is not transferred. (d) Energy is always transferred from products to reactants.
Physics
2 answers:
Lyrx [107]2 years ago
6 0

sorry im late but the correct answer would be B: energy is transferred, but it can go to the products or the reactants.

lorasvet [3.4K]2 years ago
3 0
The answer is B: energy is transferred, but it can go to the products or the reactants.
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Two strings are respectively 1.00 m and 2.00 m long. Which of the following wavelengths, in meters, could represent harmonics pr
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Answer:

5) 4.00, 2.00, 1.0

Explanation:

wave equation is given as;

F₀ = V / λ

Where;

F₀ is the fundamental frequency = first harmonic

Length of the string for first harmonic is given as;

L₀ = (¹/₂) λ  

λ  = 2 L₀

when L₀ = 1

λ  = 2 x 1 = 2m

when L₀ = 2m

λ  = 2 x 2 = 4m

For First harmonic, the wavelength is 2m, 4m

For second harmonic;

L₁ = (²/₂)λ  

L₁ = λ

When L₁ = 1

λ  = 1 m

when L₁ = 2

λ  = 2 m

For second harmonic, the wavelength is 1m, 2m

Thus, the wavelength that could represent harmonics present on both strings is 4m, 2m, 1 m

6 0
2 years ago
A graph titled Distance as a Function of Time with horizontal axis time (seconds) and vertical axis distance (meters). A straigh
yanalaym [24]

Answer:

3 m

Explanation:

6 0
1 year ago
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The air around a pool and the water in the pool receive equal amounts of energy from the sun. Why does the air experience a grea
labwork [276]

Answer:

A

Explanation:

4 0
1 year ago
Two spherical objects have masses of 200 kg and 500 kg. Their centers are separated by a distance of 25 m. Find the gravitationa
ElenaW [278]

Answer:

1.07 x 10⁻⁸N

Explanation:

Given parameters:

Mass 1 = 200kg

Mass 2  = 500kg

Distance of separation  = 25m

Unknown:

Gravitational attraction between the two bodies  = ?

Solution:

To solve this problem, we use the equation of the universal gravitation;

                 F  = \frac{G mass 1  x mass 2}{r^{2} }  

G is the universal gravitation constant  = 6.67 x 10⁻¹¹Nm²kg⁻²

r is the distance

 Now insert the parameters and solve;

    F  = \frac{6.67 x 10^{-11} x 200 x 500 }{25^{2} }   = 1.07 x 10⁻⁸N

8 0
1 year ago
An ice rescue team pulls a stranded hiker off a frozen lake by throwing him a rope and pulling him horizontally across the essen
Anuta_ua [19.1K]

Answer:T=116.84 N

Explanation:

Given

Weight of hiker =1040 N

acceleration a=1.1 m/s^2

Force exerted by Rope is equal to Tension in the rope

F_{net}=T=ma_{net}

T=\frac{1040}{g}\times 1.1

T=116.84 N

8 0
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