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Paladinen [302]
2 years ago
11

Which factors could be potential sources of error in the experiment? check all that apply.

Physics
2 answers:
Vadim26 [7]2 years ago
6 0

(A)energy lost in the lever due to friction

(C) visual estimation of height of the beanbag

(E)position of the fulcrum for the lever affecting transfer of energy

WARRIOR [948]2 years ago
6 0

Answer:

The Correct Answer is A, C, and E.

Explanation:

There are many potential sources of errors when designing and carrying pout experiments.

  • Personal error: Inaccurate observation by observers, If the data collecting has two observers and they have collected two different data which is not matching with the experiment data then it would be considered as the Observer or personal error.
  • Instrumental errors: If Calibration of the instruments is not carried out correctly then it will produce incorrect data then it will be categorized under Instrumental error of experiment.

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nikdorinn [45]
Elastic potential = 1/2 x constant x square of compression lenght
So it's 360 N/m
7 0
2 years ago
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A cube with edges exactly 2 cm long is made of material with a bulk modulus of 3.5 x 109 n/m2. when it is subjected to a pressur
Igoryamba

As we know by the formula of bulk modulus

B = \frac{\Delta P}{-\Delta V/V}

now we can rearrange it as

\Delta V/V = -\frac{\Delta P}{B}

V_f - V = -V\frac{\Delta P}{B}

now the final volume after pressure is applied is given as

V_f = V(1 - \frac{\Delta P}{B})

now we know that

\Delta P = 3 \times 10^5 Pa

V = 2^3 cm^3 = 8 cm^3

B = 3.5 \times 10^9 N/m^2

now plug in all data

V_f = 8(1 - \frac{3 \times 10^5}{3.5 \times 10^9})

V_f = 7.999 cm^3

so volume is above after pressure is applied over it

5 0
2 years ago
A baby elephant is stuck in a mud hole. to help pull it out, game keepers use a rope to apply a force f with arrowa, as part a o
Julli [10]

The two forces should be equal therefore:

2.10 * Fa = Fa + 2 * F * cos 18

simplifying the right side:

2.10 * Fa = Fa + 1.902 * F

1.10 Fa = 1.902 F

<span>F / Fa = 0.578</span>

3 0
2 years ago
What is its characteristic wavelength? [Hint: Recall that the kinetic energy of a moving object is E=12mv2, where m is the mass
Alchen [17]

Answer:

λ =  1.06 * 10^{-11} m

Explanation:

Using the De Broglie equation, the characteristic wavelength is given by:

λ = \frac{h}{p}

where

h = Planck's constant = 6.626 * 10^{-34} Js.

p = momentum

Momentum, p, can be calculated using:

p =  \sqrt{2Em}

where

m = mass of the electron = 9.11 * 10^{-31} kg

E = Energy of the electron = 13.4 keV = 13.4 * 10^3 * 1.6 * 10^{-19} J = 2.144 * 10^{-15} J

=> p = \sqrt{2 * 2.144 * 10^{-15} * 9.11 * 10^{-31}}

p = \sqrt{3.906 * 10^{-45}}

p = 6.250 * 10^{-23} kgm/s

Therefore, characteristic wavelength, λ, is:

λ =  \frac{6.626 * 10^{-34}}{6.250 * 10^{-23}}

λ =  1.06 * 10^{-11} m

4 0
2 years ago
Dawn and Aram have stretched a slinky between them and begin experimenting with waves. As the frequency of the waves is doubled
m_a_m_a [10]

Answer:

halved

Explanation:

The velocity of the a wave is obtained by multiplying the frequency and wavelength.

v=f\lambda\\\Rightarrow f=\frac{v}{\lambda}\\\Rightarrow \lambda=\frac{v}{f}

Where

v = Velocity

f = Frequency

\lambda = Wavelength

The velocity here is constant. So, if the frequency is doubled the wavelength is halved.

6 0
2 years ago
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