A large container, 120 cm deep is filled with water. If a small hole is punched in its side 77.0 cm from the top, at what initia
1 answer:
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Answer:
A. Increase in temperature is 0.0176 degree Celsius. b. the remaining energy will be lost.
Explanation:
The mass of copper block = 7kg
Initial speed = 4.0 m/s
Specific heat of copper = 0.385 j/g degree Celcius.
a. The increase in temperature is calculated below:
85% of energy is converted into internal energy.
b. The remaining 15 per cent of kinetic energy will be lost and it will be changed into other forms.
Answer:
Option B, 93 cm
Explanation:
An diagram of the seed's motion is attached to this solution.
This is very close to a projectile motion question. And the quantity to be calculated, how far along the grant a seed released would travel is called the Range.
And this would be obtained from the equations of motion,
First of, the height of the plant is related to some quantities of the motion with this relation.
H = u(y) t + 0.5g(t^2)
U(y) = initial vertical component of velocity = 0 m/s, H = height at which motion began, = 20cm = 0.2 m
That means t = √(2H/g)
The horizontal distance covered, R,
R = u(x) t + 0.5g(t^2) = u(x) t (the second part of the equation goes to zero as the vertical component of the acceleration of this motion is 0)
(substituting the t = √(2H/g) derived from above
R = u(x) √(2H/g)
Where u(x) = the initial horizontal component of the bomb's velocity = maximum initial speed, that is, 4.6 m/s, H = vertical height at which the seed was released = 20 cm = 0.2 m, g = acceleration due to gravity = 9.8 m/s2
R = 4.6 √(2×0.2/9.8) = 0.929 m = 0.93 m = 93 cm. Option B.
QED!
Answer:
Explanation:
The weekly water consumption of Kimonoski is:
The total energy required per week for hot water is: