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2 years ago

6

a falling skydiver slows from a speed of 52 m/s to 8 m/s in 0.8 sec as the parachute opens. what is the diver's acceleration and

the displacement ?

1 answer:

Cloud [144]2 years ago

8 0

I found the answers here. Hope this helps you! https://1.cdn.edl.io/sJTle6yxt3qVq7jHfdHRZJ3Xogj7ps6swBO9umNcZ6PO3SMN.docx

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How much heat Q1 is transferred by 25.0 g of water onto the skin? To compare this to the result in the previous part, continue t

hodyreva [135]

Answer:

The heat transferred from water to skin is 6913.5 J.

Explanation:

Given that,

Weight of water = 25.0 g

Suppose that water and steam, initially at 100°C, are cooled down to skin temperature, 34°C, when they come in contact with your skin. Assume that the steam condenses extremely fast. We will further assume a constant specific heat capacity c=4190 J/(kg°K) for both liquid water and steam.

We need to calculate the heat transferred from water to skin

Using formula for stream

$Q=mc\Delta T$

Put the value into the formula

$Q=25\times10^{-3}\times4190\times(373-307)$

$Q=6913.5\ J$

Hence, The heat transferred from water to skin is 6913.5 J.

3 0

2 years ago

Calculate the wavelength of a neutron that has a velocity of 200. cm/s. (the mass of a neutron = 1.675 × 10–27 kg and h = 6.63 ×

Licemer1 [7]

<span>To find the wavelength of a neutron can be calculated by using the formula Wavelength=h/m x v Where h is planck's constant m=mass of neutron v= velocity of the particle By substituting the given values Wavelength= 6.63 × 10–34 j s / 1.675 × 10–27 kg x 2 m/s^-1 Wavelength of a neutron=1.979 x 10^-7 m</span>

6 0

2 years ago

Read 2 more answers

You place a 500 g block of an unknown substance in an insulated container filled 2 kg of water. The block has an initial tempera

Nina [5.8K]

Answer:

3349J/kgC

Explanation:

Questions like these are properly handled having this fact in mind;

Heat loss = Heat gained

Quantity of heat = mcΔ∅

m = mass of subatance

c = specific heat capacity

Δ∅ = change in temperature

m₁c₁(∅₂-∅₁) = m₂c₂(∅₁-∅₃)

m₁ = mass of block = 500g = 0.5kg

c₁ = specific heat capacity of unknown substance

∅₂ = block initial temperature = 50oC

∅₁ = equilibrium temperature of block and water after mix= 25oC

m₂= mass of water = 2kg

c₂ = specific heat capacity of water = 4186J/kg C

∅₃ = intial temperature of water = 20oC

0.5c₁(50-25) = 2 x 4186(25-20)

And we can find c₁ which is the unknown specific heat capacity

c₁ = $\frac{2*4186*5}{0.5*25}$ = 3348.8J/kg C≅ 3349J/kg C

4 0

1 year ago

Kevin is a black high school senior. While walking home from a sporting event at school, he sees a police car and decides to tak

RSB [31]

Answer:

Ethnomethodology theory

Explanation:

Take note of the fact that we are told Kevin worries that the police will stop and question him even though he has not done anything wrong.

This statement shows us that Kevin already understood his society from past experiences, and thus he tries to avoid social interactions with particular member of his society (the police) who may be show discrimination towards him.

4 0

1 year ago

One species of eucalyptus tree, Eucalyptus regnans, grow to heights similar to those attained by California redwoods. Suppose a

mote1985 [20]

Answer:

The tree is 143.325 meters tall

Explanation:

The given parameters of the eucalyptus tree are;

The mass of the eucalyptus tree nut = 1.7 ounces

The speed of the nut at 50.3 m above the ground, v = 42.7 m/s

The equation for free fall is given as follows;

v² = 2·g·h

Where;

v = The velocity after falling through a height, h

g = The acceleration due to gravity = 9.8 m/s²

h = The height through which the seed has already fallen

Therefore, we have;

h = v²/(2·g) = (42.7 m/s)²/(2 × 9.8 m/s²) = 93.025 m

The height through which the seed has already fallen, h = 93.025 m

The height of the tree = h + The height of the seed above ground at the moment it was falling at 42.7 m/s

The height of the tree = 93.025 m + 50.3 m = 143.325 m

The height of the tree = 143.325 m.

4 0

1 year ago