Two workhorses tow a barge along a straight canal. Each horse exerts a constant force of magnitude F, and the tow ropes make an
1 answer:
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The current flowing in silicon bar is 2.02 10^-12 A.
<u>Explanation:</u>
Length of silicon bar, l = 10 μm = 0.001 cm
Free electron density, Ne = 104 cm^3
Hole density, Nh = 1016 cm^3
μn = 1200 cm^2 / V s
μр = 500 cm^2 / V s
The total current flowing in the bar is the sum of the drift current due to the hole and the electrons.
J = Je + Jh
J = n qE μn + p qE μp
where, n and p are electron and hole densities.
J = Eq (n μn + p μp)
we know that E = V / l
So, J = (V / l) q (n μn + p μp)
J = (1.6 10^-19) / 0.001 (104
1200 + 1016
500)
J = 1012480 10^-16 A / m^2.
or
J = 1.01 10^-9 A / m^2
Current, I = JA
A is the area of bar, A = 20 μm = 0.002 cm
I = 1.01 10^-9
0.002 = 2.02
10^-12
So, the current flowing in silicon bar is 2.02 10^-12 A.
Answer:
Part a)
Part b)
Part c)
Explanation:
Part a)
As we know that it is having constant torque so here the time taken by it to accelerate is given as
Part b)
angular displacement is given as
Part c)
As we know that the angular deceleration produced by the brakes is given as
now we have
As we know that
so we have
Answer:
0.69444 m, 0.08152 m, 0.32407 m, 0.03804 m
Explanation:
v = Velocity of sound
f = Frequency
Length of vocal tract is given by
At f = 270 Hz v = 750 m/s
At f = 2300 Hz v = 750 m/s
At f = 270 Hz v = 350 m/s
At f = 2300 Hz v = 350 m/s