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g100num [7]
2 years ago
15

Which of the following best describes an action-reaction pair? A. The Moon Pulls on Earth, and Earth pulls back on the moon. B.

A bed sits on the floor, and Earth's gravity pulls down on the bed. C. A television pushes down on a shelf, and the shelf pulls the television down. D. You kick a wall, and the wall pulls on your foot.
Physics
2 answers:
Papessa [141]2 years ago
4 0
An action-reaction pair would be a pair in which one of the elements exerts a force on the other element (action), and then the other element would respond to this force by exerting another force in the opposite direction (reaction).

From the given choices, we will see that:
For choice A, the moon exerts a force on the earth by pulling it (action) and the earth responds to this force by pulling the moon (reaction in opposite direction of the action).

Therefore, the correct choice would be: 
A. <span>The Moon Pulls on Earth, and Earth pulls back on the moon.</span>
olchik [2.2K]2 years ago
3 0

Answer:

You push on a car and the car pushes back on you

Explanation:

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Based on the free-body diagram, the net force acting on this wheelbarrow is {blank} N.
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diagram?

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A 10N force pulls to the right and friction opposes 2N. If the object is 20kg,find the acceleraton.
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Who pays for Government workers that work on alcohol impaired driving cases?
Shalnov [3]

Answer: Taxpayers

Explanation:

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8 0
1 year ago
550 J of work must be done to compress a gas to half its initial volume at constant temperature. How much work must be done to c
Over [174]

Answer:

The amount of work that must be done to compress the gas 11 times less than its initial pressure is 909.091 J

Explanation:

The given variables are

Work done = 550 J

Volume change = V₂ - V₁ = -0.5V₁

Thus the product of pressure and volume change = work done by gas, thus

P × -0.5V₁ = 500 J

Hence -PV₁ = 1000 J

also P₁/V₁ = P₂/V₂ but V₂ = 0.5V₁ Therefore  P₁/V₁ = P₂/0.5V₁ or P₁ = 2P₂

Also to compress the gas by a factor of 11 we have

P (V₂ - V₁) = P×(V₁/11 -V₁) = P(11V₁ - V₁)/11 = P×-10V₁/11 = -PV₁×10/11 = 1000 J ×10/11  = 909.091 J of work

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