The amount of work done can be solved using the formula:
Work = Force x Distance = Change in kinetic energy
Kinetic energy can be solved using the formula: KE = (1/2)*m*v^2
So, change in kinetic energy = (1/2)*m*(Vf)^2 - (1/2)*m*(Vo)^2
Where:
Vf = final velocity = 90 kph = 25 m/s
Vo = initial velocity = 72 kph = 20 m/s
substituting the given values:
Work = (1/2)*2500*(25^2) - (1/2)*2500*(20^2) = 281250 J, which can also be expressed as 2.8 x 10^5 Joules.
Among the choices, the correct answer is A.
The parcel will undergo projectile motion, which means that it will have motion in both the horizontal and vertical direction.
First, we determine how long the parcel will fall using:
s = ut + 1/2 at²
where s will be the height, u is the initial vertical velocity of the parcel (0), t is the time of fall and a is the acceleration due to gravity.
5.5 = (0)(t) + 1/2 (9.81)(t)²
t = 1.06 seconds
Now, we may use this time to determine the horizontal distance covered by the parcel by using:
distance = velocity * time
The horizontal velocity of the parcel will be equal to the horizontal velocity of the cruise liner.
Distance = 10 * 1.06
Distance = 10.6 meters
The boat should be 10.6 meters away horizontally from the point of release.
Answer:
(a) 19.62 N
(b) Box moves down the slope
(c) 24.43 N
Explanation:
(a)
2 Kg box causes tension
![T=mgwhere m is mass, g is gravitational force taken as 9.81T=2*9.81 =19.62 N (b) Block mass of 4 Kg [tex]T'-mg sin \theta=0](https://tex.z-dn.net/?f=T%3Dmg%3C%2Fp%3E%3Cp%3Ewhere%20m%20is%20mass%2C%20g%20is%20gravitational%20force%20taken%20as%209.81%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3ET%3D2%2A9.81%20%3D19.62%20N%20%20%3C%2Fp%3E%3Cp%3E%28b%29%20%20%3C%2Fp%3E%3Cp%3EBlock%20mass%20of%204%20Kg%20%20%3C%2Fp%3E%3Cp%3E%5Btex%5DT%27-mg%20sin%20%5Ctheta%3D0)
hence 
where m is mass and g is gravitational force
T'=4*9.81 sin 35= 22.5071 N
Since T' is greater than 
, then the box moves down the slope
(c)
Acceleration a= 
When moving, the box will exert force T"= 
T"= 4*9.81 sin 35 +(4*0.48)= 24.43 N
The gravitational force exerted on the satellite is called the centrifugal force, the force keeping it orbiting to the planet. Its formula is F= mass times the square of the velocity all over the radius.Thus,
F = 2400 * 6670^2 * (1/8.92x10^6)
F = 11,970 N
I hope I was able to help you. Have a good day.
B.
The child is too old to be gaining something from the screen time.
