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ivanzaharov [21]
2 years ago
11

Levi and Clara are trying to move a very heavy box. Levi is pushing the box with a force of 30 N, and Clara is pulling the box w

ith a force of 50 N. The box exerts a frictional force of 65 N.
Which best explains the forces?
Answer
There is a net force of 15 N allowing Levi and Clara to move the box.
Physics
2 answers:
san4es73 [151]2 years ago
7 0

Answer:

There is a net force of 15 N allowing Levi and Clara to move the box.

Explanation:

Komok [63]2 years ago
5 0
There is a ner force of 15 N allowing Levi and Clara to mobe the box.
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A child is riding a bike at a speed of 6m/s with a total kinetic energy of 1224J. If the mass of the child is 30kg, what is the
UkoKoshka [18]

Answer:

 Mass of bike = 38 kg.

Explanation:

Kinetic energy is given by the expression, KE = \frac{1}{2} mv^2, where m is the mass and v is the velocity.

Here speed of child riding bike = 6 m/s

Mass of child = 30 kg

Total kinetic energy = 1224 J

Let the mass of bike be, m kg

So, total mass of child and bike = (m + 30) kg

Substituting,

  1224 = \frac{1}{2}* (m+30)*6^2\\ \\ m+30=68\\ \\ m=38kg

So, mass of bike = 38 kg.

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Drying of Cassava (Tapioca) Root. Tapioca flour is used in many countries for bread and similar products. The flour is made by d
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If the Force exerted by the intern is doubled and the distance is halved, does the done by the intern increase, decrease, or rem
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Remain the same

Explanation:

If the force exerted by the intern is doubled and the distance is halved, the work done by the intern remains the same.

 Work done is the force applied to move a body through a distance.

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where F is the applied force

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Now;

if:

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Input the parameter:

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learn more:

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the initial kinetic energy of an object moving on a horizontal surface is K. Friction between the object and the surface causes
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Answer:

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A 202 kg bumper car moving right at 8.50 m/s collides with a 355 kg car at rest. Afterwards, the 355 kg car moves right at 5.80
Sidana [21]

Explanation:

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Initial speed of the bumper car, u₁ = 8.5 m/s

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Initial velocity of the other car is 0 as it at rest, u₂ = 0

Final velocity of the other car after collision, v₂ = 5.8 m/s

Let p₁ is momentum of of 202 kg car, p₁ = m₁v₁

Using the conservation of linear momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

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