Answer:
Explanation:
Given
mass flow rate=0.3 kg/s
diameter of pipe=5 cm
length of pipe=10 m
Inside temperature=22
Pipe surface =100
Temperature drop=30
specific heat of vapor(c)=2190 J/kg.k
heat supplied
Heat due to convection =hA(100-30)
19,710=122.538 h
Answer:
Canyon is 50.176 meter deep.
Explanation:
The students is standing on the rim of the canyon and drops down a rock from the rim(cliff). We have to find what is the depth of the canyon i.e. how much below is the ground from the cliff.
Given data:
Time = t = 3.2 s
Initial velocity = = 0 m/s
Gravitational acceleration = g = 9.8 m/s²
Height = h = ?
According to second equation of motion
As initial velocity is zero, So the first term of right hand side of above equation equal to zero
h = (0.5)(9.8)(3.2)²
h = 50.176 m
This means, the rock traveled 50.176 meters to reach the bottom of the Canyon. So, the Canyon is 50.176 meter deep.