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1 year ago

A block of size 20m x 10 mx 5 m exerts a force of 30N. Calculate the

Physics

1 answer:

Orlov [11]1 year ago

3 0

Answer:

We know that force applied per unit area is called pressure.

Pressure = Force/ Area

When force is constant than pressure is inversely proportional to area.

1- Calculating the area of three face:

A1 = 20m x 10 m =200 Square meter

A2 = 10 mx 5 m = 50 Square meter

A3 = 20m x 5 m = 100 Square meter

Therefore A1 is maximum and A2 is minimum.

2- Calculate pressure:

P = F/ A1 = 30 / 200 = 0.15 Nm⁻² ( minimum pressure)

P = F / A2 = 30 / 50 = 0.6 Nm⁻² ( maximum pressure)

Hence greater the area less will be the pressure and vice versa.

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A long, straight wire carrying a current of 3.45 A moves with a constant speed v to the right. A 5-turn circular coil of diamete

d1i1m1o1n [39]

Answer:

I = 69.3 μA

Explanation:

Current through the straight wire, I = 3.45 A

Number of turns, N = 5 turns

Diameter of the coil, D = 1.25 cm

Resistance of the coil, $R = 3.25 \mu ohms$

Distance of the wire from the center of the coil, d = 20 cm = 0.2 m

The magnetic field, B₁, when the wire is at a distance, d, from the center of the coil.

$B_{1} = \frac{\mu_{0}I }{2\pi d}$

$B_{1} = \frac{4\pi* 10^{-7} *3.45 }{2\pi *0.2}\\B_{1} =0.00000345 T$

Magnetic field B₂ when the wire is at a distance, 2d from the center of the coil

$B_{2} = \frac{\mu_{0}I }{2\pi(2d)) } \\B_{2} = \frac{\mu_{0}I }{4\pi d } \\$

$B_{2} = \frac{4\pi* 10^{-7} *3.45 }{2\pi *2*0.2}\\B_{2} = 0.000001725 T$

Change in the magnetic field, ΔB = B₂ - B₁ = 0.00001725 - 0.0000345

ΔB = -0.000001725

Induced current, $I = \frac{E}{R}$

E = -N (Δ∅)/Δt

Δ∅ = A ΔB

Area, A = πr²

diameter, d = 0.0125 m

Radius, r = 0.00625 m

A = π* 0.00625²

A = 0.0001227 m²

Δ∅ = -0.000001725 * 0.0001227

Δ∅ = -211.6575 * 10⁻¹²

E = -N (Δ∅)/Δt

$E = -5\frac{-211.6575 * 10^{-12} }{4.70} \\E = 225.17 * 10^{-12} V$

Resistance, R = 3.25 μ ohms = 3.25 * 10⁻⁶ ohms

I = E/R

$I = \frac{225.17 * 10^{-12} }{3.25 * 10^{-6} }$

I = 0.0000693 A

I = 69 .3 * 10⁻⁶A

I = 69.3 μA

3 0

2 years ago

In Physics lab, Ellen has been given the task of constructing a simple motor. She must find common household items at home and b

Aleks [24]

Answer:

a) battery-->electrical current-->copper wire rotor -->magnet--> mechanical energy

Explanation:

6 0

2 years ago

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An unspecified force causes a 0.20-kg object to accelerate at 0.40 m/s2. If 0.30 kg is added to the 0.20-kg object and the force

Naddik [55]

Answer:

a = 0.16

Explanation:

given,

mass of the object 1 = 0.2 kg

mass of the object 2 = 0.3 kg

acceleration when force is on 0.2 kg = 0.4 m/s²

acceleration when both mass are combine = ?

F = m a

F = 0.2 × 0.4

F = 0.08 N

force acting is same and total mass = 0.2 + 0.3 = 0.5 Kg

F = m a

$a = \dfrac{F}{m}$

$a = \dfrac{0.08}{0.5}$

a = 0.16 m/s²

the acceleration acting when both the body is attached is a = 0.16

4 0

2 years ago

The position of a particle moving along the x axis may be determined from the expression x(t) = btu + ctv, where x will be in me

KIM [24]

As per given equation we have

$x = bt^u + ct^v$

now as per the dimensional analysis we can say that dimension of right side of equation must be equal to left side of the equation

now as per left side of equation its dimension is same as length or meter

now we can say it should be meter on right side also

$bt^u = M^0L^1T^0$

$b*T^8 = M^0L^1T^0$

$b = M^0L^1T^{-8}$

similarly for other term we have

$ct^v = M^0L^1T^0$

$c*T^7 = M^0L^1T^0$

$c = M^0L^1T^{-7}$

so above are the dimensions of b and c

8 0

1 year ago

Use the periodic table and your knowledge of isotopes to complete these statements.

klasskru [66]

Use the periodic table and your knowledge of isotopes to complete these statements.

When polonium-210 emits an alpha particle, the child isotope has an atomic mass of ⇒ 206.

I-131 undergoes beta-minus decay. The chemical symbol for the new element is ⇒ Xe.

Fluorine-18 undergoes beta-plus decay. The child isotope has an atomic mass of ⇒ 18.

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2 years ago

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