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Anarel [89]
2 years ago
12

what velocity must a 1340kg car have in order to havw the same momentum as a 2680 kg truck traveling at a velocity of 15m/s to t

he west?
Physics
1 answer:
kykrilka [37]2 years ago
6 0
Car with a mass of 1210 kg moving at a velocity of 51 m/s.
2. What velocity must a 1340 kg car have in order to have the same momentum as a 2680 kg truck traveling at a velocity of 15 m/s to the west? 3.0 X 10^1 m/s to the west.

Hope i helped
Have a good day :)

 
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A cyclist traveling at 5m/s uniformly accelerates up to 10 m/s in 2 seconds. Each tire of the bike has a 35 cm radius, and a sma
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Answer:

a=2.5\ m/s^2

Explanation:

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Final speed, v = 10 m/s

Time, t = 2 s

The radius of the tire of the bike, r = 35 cm

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a=\dfrac{v-u}t{}\\\\a=\dfrac{10-5}{2}\\\\a=2.5\ m/s^2

So, the required angular acceleration of the pebble is equal to 2.5\ m/s^2.

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The velocity component with which a projectile covers certain horizontal distance is maximum at the moment of? a) Hitting the gr
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A) hitting the ground
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a torch bulb is rated 2.5V and 750mA. Calculate its power,its resistance and the energy consumed if this bulb lighted for 4 hour
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Substituting the values to the given, 
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Calculating the power, we have P = IV

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: The truck is to be towed using two ropes. Determine the magnitudes of forces FA and FB acting on each rope in order to develop
Sholpan [36]

Answer:

Fa=774 N

Fb=346 N

Explanation:

We will solve this problem by equating forces on each axis.

  1. On x-axis let forces in positive x-direction be positive and forces in negative x-direction be negative
  2. On y-axis let forces in positive y-direction be positive and forces in negative y-direction be negative

While towing we know that car is mot moving in y-direction so net force in y-axis must be zero

⇒∑Fy=0

⇒Fa*sin(50)-Fb*sin(20)=0

⇒Fa*sin(50)=Fb*sin(20)

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Given that resultant force on car is 950N in positive x-direction

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⇒Fb*(2.24*cos(20)+cos(50))=950

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      =773.93

Therefore approximately, Fa=774 N and Fb=346 N

5 0
2 years ago
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