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1 year ago

9

A motorcycle of mass 100 kilograms travels around a flat, circular track of radius 10 meters with a constant speed of 20 meters

per second. What force is required to keep the motorcycle moving in a circular path at this speed?

2 answers:

JulijaS [17]1 year ago

8 0

Answer:

100/10 = 10 , 10 × 10 = 100÷20 = 5

I'm pretty sure its wrong

krok68 [10]1 year ago

5 0

Answer: pretty sure is 4000N.

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If gravity between the Sun and Earth suddenly vanished, Earth would continue moving in

Ksenya-84 [330]

Answer:

Earth would continue moving by uniform motion, with constant velocity, in a straight line

Explanation:

The question can be answered by using Newton's first law of motion, also known as law of inertia, which states that:

"an object keeps its state of rest or of uniform motion in a straight line unless acted upon by an external net force different from zero"

This means that if there are no forces acting on an object, the object stays at rest (if it was not moving previously) or it continues moving with same velocity (if it was already moving) in a straight line.

In this problem, the Earth is initially moving around the Sun, with a certain tangential velocity v. When the Sun disappears, the force of gravity that was keeping the Earth in circular motion disappears too: therefore, there are no more forces acting on the Earth, and so by the 1st law of Newton, the Earth will continue moving with same velocity v in a straight line.

6 0

1 year ago

If you take any pitch on the keyboard, the next occurrence of the same letter name going towards the left (down) will vibrate:

NikAS [45]

Answer:

A. Twice as slow

Explanation:

8 0

1 year ago

A car drives 16 miles south and then 12 miles west. What is the magnitude of the car’s displacement? 4 miles 16 miles 20 miles 2

Ostrovityanka [42]

For this case, what we can do is use the Pythagorean theorem to find the magnitude of the displacement of the car.
We have then
$d ^ 2 = 16 ^ 2 + 12 ^ 2
$
From here, we clear the value of d.
We have then:
$d = \sqrt{16 ^ 2 + 12 ^ 2} 
$
Rewriting:
$d = \sqrt{256 + 144}$
$d = \sqrt{400}$
$d = 20 miles
$
Answer:
The magnitude of the car's displacement is:
d = 20 miles

7 0

1 year ago

Read 2 more answers

A woman living in a third-story apartment is moving out. Rather than carrying everything down the stairs, she decides to pack he

Flura [38]

Answer:

T = 480.2N

Explanation:

In order to find the required force, you take into account that the sum of forces must be equal to zero if the object has a constant speed.

The forces on the boxes are:

$T-Mg=0$ (1)

T: tension of the rope

M: mass of the boxes 0= 49kg

g: gravitational acceleration = 9.8m/s^2

The pulley is frictionless, then, you can assume that the tension of the rope T, is equal to the force that the woman makes.

By using the equation (1) you obtain:

$T=Mg=(49kg)(9.8m/s^2)=480.2N$

The woman needs to pull the rope at 480.2N

8 0

1 year ago

When a test charge q0 = 2 nC is placed at the origin, it experiences a force of 8 times 10-4 N in the positive y direction. What

ser-zykov [4K]

Answer:

Electric field, $E=4\times 10^5\ N/C$

Explanation:

It is given that,

Magnitude of charge, $q_o=2\ nC=2\times 10^{-9}\ C$

Force experienced, $F=8\times 10^{-4}\ N$

We need to find the electric field at the origin. It is given by :

$F=q_o\times E$

$E=\dfrac{F}{q_o}$

$E=\dfrac{8\times 10^{-4}}{2\times 10^{-9}}$

$E=4\times 10^5\ N/C$

So, the electric field at the origin is $4\times 10^5\ N/C$ . Hence, this is the required solution.

3 0

1 year ago