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Nikitich [7]
2 years ago
14

Use the drop-down menus to complete the statements. The atoms in a solid . The arrangement of atoms in a solid causes it to have

a definite . Solids in which the atoms have no particular order or pattern are called solids.
Physics
2 answers:
Natalija [7]2 years ago
8 0

Answer:The atoms in a solid  .

remain in fixed position

The arrangement of atoms in a solid causes it to have a definite  .

 shape and value

Solids in which the atoms have no particular order or pattern are called   solid

noncrystalline

Explanation:

Guest
1 year ago
edge 2021
timama [110]2 years ago
5 0

Answer:

The atoms in a solid remain in fixed position .

The arrangement of atoms in a solid causes it to have a definite  shape and volume .

 

Solids in which the atoms have no particular order or pattern are called   noncrystalline solids.

Explanation:

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Its bituminous coal good luck :;;;;;;)
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A beam of electrons moves at right angles to a magnetic field of 4.5 × 10-2 tesla. If the electrons have a velocity of 6.5 × 106
defon

Answer:

4.7\cdot 10^{-14}N

Explanation:

For a charge moving perpendicularly to a magnetic field, the force experienced by the charge is given by:

F=qvB

where

q is the magnitude of the charge

v is the velocity

B is the magnetic field strength

In this problem,

q=1.6\cdot 10^{-19} C

v=6.5\cdot 10^6 m/s

B=4.5\cdot 10^{-2} T

So the force experienced by the electrons is

F=(1.6\cdot 10^{-19}C)(6.5\cdot 10^6 m/s)(4.5\cdot 10^{-2} T)=4.7\cdot 10^{-14}N

3 0
2 years ago
A truck traveling at a constant speed of 40.0 km/h applies its brakes and comes to a complete stop in 5.0 s.
I am Lyosha [343]

Answer:

Part a)

v = 11.11 m/s

Part c)

a = -2.22 m/s^2

This mean the truck is decelerating and its speed is decreasing

Part e)

t = 13.89 s

Part f)

d = 77.14 m

Explanation:

Part a)

Speed of the truck is given as

v = 40 km/h

as we know that

1 km = 1000 m

1 h = 3600 s

so we will have

v =40 \times \frac{1000}{3600} m/s

v = 11.11 m/s

Part c)

Average acceleration is given as

a = \frac{v_f - v_i}{t}

now we have

a = \frac{0 - 11.11}{5}

a = -2.22 m/s^2

Part e)

as we know that it is uniform acceleration

so we can say

v_f - v_i = at

11.11 - 0 = 0.80 t

t = 13.89 s

Part f)

distance traveled by the truck is given as

d = \frac{1}{2}at^2

d = \frac{1}{2}(0.80)(13.89^2)

d = 77.14 m

4 0
2 years ago
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Ari, a young patient who is regularly treated by a psychiatrist, feels compelled to carry out repetitive tasks the same way very
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1. Do alto de uma plataforma com 15m de altura, é lançado horizontalmente um projéctil. Pretende-se atingir um alvo localizado n
sveta [45]

Answer:

(a). The initial velocity is 28.58m/s

(b). The speed when touching the ground is 33.3m/s.

Explanation:

The equations governing the position of the projectile are

(1).\: x =v_0t

(2).\: y= 15m-\dfrac{1}{2}gt^2

where v_0 is the initial velocity.

(a).

When the projectile hits the 50m mark, y=0; therefore,

0=15-\dfrac{1}{2}gt^2

solving for t we get:

t= 1.75s.

Thus, the projectile must hit the 50m mark in 1.75s, and this condition demands from equation (1) that

50m = v_0(1.75s)

which gives

\boxed{v_0 = 28.58m/s.}

(b).

The horizontal velocity remains unchanged just before the projectile touches the ground because gravity acts only along the vertical direction; therefore,

v_x = 28.58m/s.

the vertical component of the velocity is

v_y = gt \\v_y = (9.8m/s^2)(1.75s)\\\\{v_y = 17.15m/s.

which gives a speed v of

v = \sqrt{v_x^2+v_y^2}

\boxed{v =33.3m/s.}

4 0
1 year ago
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