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zhuklara [117]
2 years ago
14

A charge of 4 nc is placed uniformly on a square sheet of nonconducting material of side 17 cm in the yz plane. (a) what is the

surface charge density sigma ?
Physics
1 answer:
Ratling [72]2 years ago
8 0

The charge density of the sheet is 1.384×10⁻⁷C/m².

Charge density is defined as the charge per unit area.

The sheet is a square of length  l=17 cm.

Calculate the area A of the sheet .

A=l^2=(17 cm)^2= (17*10^-^2m)^2=0.0289 m^2

The charge Q on the sheet is

Q=4nC=4*10^-^9C

The charge density σ is given by,

\sigma=\frac{Q}{A}

Substitute 4×10⁻⁹C for Q and 0.0289 m² for A.

\sigma=\frac{Q}{A}\\ =\frac{4*10^-^9C}{0.0289 m^2} \\ =1.389*10^-^7C/m^2

Thus, the charge density of the sheet is <u>1.384×10⁻⁷C/m².</u>

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Answer:

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a) Earth

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The neutral table tennis ball will become polarized, with positive charges toward the glass rod. The correct answer between all the choices given is the last choice or letter D. I am hoping that this answer has satisfied your query and it will be able to help you, and if you would like, feel free to ask another question.

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The fundamental frequency of a resonating pipe is 150 Hz, and the next higher resonant frequencies are 300 Hz and 450 Hz. From t
olasank [31]

Answer:

Explanation:

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for   fundamental note   2l = wavelength

frequency n = V / Wave length , V is velocity of sound.

f₁ = V / 2I

for   first overtone  note   2l /2  = wavelength

wavelength = l

frequency = V / wavelength

f₂ = V / l

for   second  overtone  note   2l /3  = wavelength

wavelength = 2l /3

frequency = V / wavelength

f₃ =  3V /2l

f₁ : f₂ : f₃ : : 1 : 2 : 3

In case of closed organ pipe ,

for fundamental note   l = 4 x wavelength

frequency n = V / Wave length , V is velocity of sound.

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for   first overtone  note   l /  =   3 wavelength / 4

wavelength = 4 l / 3

frequency = V / wavelength

f₂ =3 V /4 l

for   second  overtone  note   l   =  5 wavelength /4

wavelength = 5l /4

frequency = V / wavelength

f₃ =  5 V /4 l

f₁ : f₂ : f₃ : : 1 : 3 : 5.

In case of open organ pipe , frequencies are in any integral ratio.

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A bodybuilder lifts a 10 N weight a distance of 2.5 m. <br> How much energy has the weight gained?
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Answer:

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Explanation:

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