An electret is similar to a magnet, but rather than being permanently magnetized, it has a permanent electric dipole moment. Sup
2 answers:
Answer:
F = 9.216 × 10⁻³ N
Explanation:
given,
dipole moment = 1 × 10⁻⁷ Cm
distance apart from +80 nC charge = 25 cm
to calculate the magnitude of electric force
Electric field due to dipole
E = 1.152 × 10⁵ N/C
electric force on the ball
F = E q
= 1.152 × 10⁵ × 80 × 10⁻⁹
F = 9.216 × 10⁻³ N
Hence, the electric force is equal to F = 9.216 × 10⁻³ N
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Electric charge on the plastic cube:
Explanation:
The electric potential around a charged sphere (such as the Van der Graaf) generator is given by
where
k is the Coulomb's constant
Q is the charge on the sphere
r is the distance from the centre of the sphere
Here we have:
V = 200,000 V on the surface of the sphere, so at r = 12.0 cm
We need to find the voltage V' at 2.0 cm from the edge of the sphere, so at
r' = 12.0 + 2.0 = 14.0 cm
Since the voltage is inversely proportional to r, we can use:
This is the potential at the location of the plastic cube.
Now we can use the law of conservation of energy, which states that the initial electric potential energy of the cube is totally converted into kinetic energy when the plastic cube is at infinite distance from the generator. So we can write:
where:
q is the charge on the plastic cube
V' is the potential at the location of the cube
m = 5.0 g = 0.005 kg is the mass of the cube
v = 3.0 m/s is the final speed of the cube
Solving for q, we find the charge on the cube:
Learn more about electric fields:
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Answer:
The charge to mass ratio is
Explanation:
We need to find how much charge is contained in the electron per unit of mass, to do this we divide the charge in an electron and the mass of an electron:
Answers:
A. A car driving at steady speed on a straight and level road.
B. A car driving at steady speed up a 10∘ incline.
Explanation:
An object is said to be in an inertial reference frame if the net force acting on the object is zero. According to Newton's second law, this also means that the acceleration of the object is also zero:
Since F=0, a=0 as well.
Let's now analyze each case.
A. A car driving at steady speed on a straight and level road. --> YES: this is an inertial reference frame, because the car is keeping a constant speed and a constant direction, so its velocity is not changing, and its acceleration is zero.
B. A car driving at steady speed up a 10∘ incline. --> YES: this is an inertial reference frame, because the car is keeping a constant speed and a constant direction, so its velocity is not changing, and its acceleration is zero.
C. A car speeding up after leaving a stop sign. --> NO: this is not an intertial reference frame, because the car is speeding up, so it is accelerating.
D. A car driving at steady speed around a curve. --> NO: this is not an inertial reference frame, because the car is changing direction, therefore its velocity is changing and so the car is accelerating.
So the only two choices which are correct are A and B.