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Scrat [10]
2 years ago
6

How much gravitational potential energy does a 45.2 kg object have when it is 21.9m above the ground?

Physics
1 answer:
Blizzard [7]2 years ago
6 0

Answer:

Explanation:

The formula for gravitational potential energy is

Ep = m · g · h   Assuming that the acceleration is g = 10m/s²

Ep = 45.4 · 10 · 21.9 = 9,942.6 J

God is with you!!!

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Devonte pushes a wheelbarrow with 830 W of power. How much work is required to get the wheelbarrow across the yard in 11 s? Roun
xxMikexx [17]

Answer: 9130 joules

Explanation:

Workdone by wheelbarrow = ?

Time = 11 seconds

Power = 830 watts

Recall that power is the rate of doing work. Thus, power is workdone divided by time taken.

i.e Power = (workdone/time)

830 watts = Workdone / 11 seconds

Workdone = 830 watts x 11 seconds

Workdone = 9130 joules

Thus, 9130 joules of work is required to get the wheelbarrow across the yard.

8 0
2 years ago
Read 2 more answers
What is the average force (average with respect to height of the barbell from the ground) exerted by the weightlifter in the pro
Novay_Z [31]

This question is incomplete, the complete question is;

A weightlifter holds a 1,300 N barbell 1 meter above the ground. One end of a 2-meter-long chain hangs from the center of the barbell. The chain has a total weight of 400 N. How much work (in J) is required to lift the barbell to a height of 2 m?

What is the average force (average with respect to height of the barbell from the ground) exerted by the weightlifter in the process?

Answer: Average force exerted by the weightlifter in the process = 1600N

Explanation:

To find Work done to lift a barbell and half of the hanging chain we say;

W₁ = ( 1300N + (1/2 × 400N)) × 1m

W₁ = (1300 + 200) Nm

W₁ = 1500J

now work done to lift the upper half of the chain we say:

W₂ = (1/2 × 400N) ×  (1/2 × 1m)

W₂ = 200N × 0.5m

W₂ = 100J

So total work done will be

W = W₁ + W₂

W = 1500J + 100J

W = 1600J

To find the average force exerted by the weight lifter, we say;

F = W/D

F = (1600 / 1m) N

F = 1600N

∴Average force = 1600N

6 0
2 years ago
Nikolas had an idea that he could use the compressed carbon dioxide in a fire extinguisher to propel him on his skateboard.
Vikentia [17]
The Newton’s law Nikolas would use to come up with this idea is the <span>Third law that states:

</span><span>When one body exerts a force on a second body, the second body simultaneously exerts a force equal in magnitude and opposite in direction on the first body.
</span>
So, in this case, let's name the first Body A which is the skateboard and the second body B which is <span>the compressed carbon dioxide in a fire extinguisher. Then, as shown in the figure below, according to the Third law:

</span>FA = -FB<span>

</span>

8 0
2 years ago
Read 2 more answers
If the temperature of an ideal gas is increased from 200 K to 600 K, what happens to the rms speed of the molecules? (a) It incr
lawyer [7]

Answer: (d) It is !3 times the original speed.

Explanation: The rms speed of a gas is related to its temperature by the formulae below;

U(r.m.s) =√(3RT)/M

Where;

T represents the temperature.

R represents the gas constant.

M represents the molar mass of the gas.

Therefore, if the temperature increases from 200k to 600k

The temperature has then increased by a factor of 3,

However, we must note that temperature in the formulae is included in the square-root

Recall,

U(r.m.s) =√(3RT)/M

Consequently, temperature (T) can now be represented by (3T).

The inference drawn from this is that the root-mean-square speed would increase by a factor of √3

Therefore, option (d) is correct.

7 0
2 years ago
Read 2 more answers
A fast Humvee drove from desert A to desert B. For the first 12
Zina [86]

Answer:

v = 172 km/h

Explanation:

For the first 12  hours, it traveled at an average speed of 185 km/h. Let d₁ is distance. So,

d_1=v_1\times t_1\\\\d_1=185\ km/h\times 12\ h\\\\d_1=2220\ km

For the  next 13 hours, it traveled at an average speed of 160 km/h. Let d₂ is the distance. So,

d_2=v_2\times t_2\\\\d_2=160\ km/h\times 13\ h\\\\d_2=2080\ km

Average speed = total distance/time taken

So,

v=\dfrac{d_1+d_2}{t_1+t_2}\\\\v=\dfrac{2220+2080}{12+13}\\\\v=172\ km/h

So, the average speed of the whole journey is 172 km/h.

4 0
2 years ago
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