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BartSMP [9]
2 years ago
6

Scientific knowledge builds upon previous knowledge."

Physics
1 answer:
notka56 [123]2 years ago
4 0

Answer:

B

Explanation:

Magic

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On the planet Abby, there is an homozygous lethal condition known as Gumball. Individuals with this condition chew gum till thei
Ipatiy [6.2K]

Answer:

D. 0.7 would be wild-type healthy

E. 0.3 would be affected Gg

Explanation:

Using the Punnett square we cross an homozygous male (gg), that is always healthy vs an heterozygous female (Gg). The result is 2 gg individuals, and 2 Gg individuals. Both gg individuals are healthy.

In a population of 1000 Gg individuals, 600 show the Gumball phenotype (unhealthy). It means that from the two heterozygous Gg (from the Punnett square), 1.2 show the unhealthy phenotype.

Again, from the Punnett square we have 4 individuals, that represent the 100%. 1.2 are unhealthy Gg, and represent 30% in F1.

This 30%, is equivalent to 0.3, that is the option E.

100 - 30 % = 70 %.  This is 0.7 for healthy wild-type, option D.

6 0
2 years ago
You are pulling your little sister on her sled across an icy (frictionless) surface. When you exert a constant horizontal force
Tpy6a [65]

Answer:

Mass of Little Sister = 44.17 kg

Explanation:

From Newton's second law of motion, the magnitude of force applied on the sled is given by the following formula:

F = ma

where,

F = Force Applied = 120 N

a = Acceleration = 2.3 m/s²

m = Mass of Sled + Mass of Little Sister = 8 kg + Mass of Little Sister

Therefore,

120 N = (2.3 m/s²)(8 kg + Mass of Little Sister)

(120 N)/(2.3 m/s²) = 8 kg + Mass of Little Sister

Mass of Little Sister = 52.17 kg - 8 kg

<u>Mass of Little Sister = 44.17 kg</u>

4 0
2 years ago
Two spherical objects have masses of 200 kg and 500 kg. Their centers are separated by a distance of 25 m. Find the gravitationa
ElenaW [278]

Answer:

1.07 x 10⁻⁸N

Explanation:

Given parameters:

Mass 1 = 200kg

Mass 2  = 500kg

Distance of separation  = 25m

Unknown:

Gravitational attraction between the two bodies  = ?

Solution:

To solve this problem, we use the equation of the universal gravitation;

                 F  = \frac{G mass 1  x mass 2}{r^{2} }  

G is the universal gravitation constant  = 6.67 x 10⁻¹¹Nm²kg⁻²

r is the distance

 Now insert the parameters and solve;

    F  = \frac{6.67 x 10^{-11} x 200 x 500 }{25^{2} }   = 1.07 x 10⁻⁸N

8 0
1 year ago
A satellite that orbits Earth with a speed of v0 must be in an orbit of radius 8RE to maintain a circular orbit, where RE is the
NISA [10]

Answer:

1.024 × 10⁸ m

Explanation:

The velocity v₀ of the orbit 8RE is v₀ = 8REω where ω = angular speed.

So, ω =  v₀/8RE

For the orbit with radius R for it to maintain a circular orbit and velocity 2v₀, we have

2v₀ = Rω

substituting ω =  v₀/8RE into the equation, we have

2v₀ = v₀R/8RE

dividing both sides by v₀, we have

2v₀/v₀ = R/8RE

2 = R/8RE

So, R = 2 × 8RE

R = 16RE

substituting RE = 6.4 × 10⁶ m

R = 16RE

= 16 × 6.4 × 10⁶ m

= 102.4 × 10⁶ m

= 1.024 × 10⁸ m

8 0
2 years ago
Adam is teeing off on hole number two. The hole is 390 yards away. It is a par four hole. What club should he use to tee off? Ex
kkurt [141]

Answer:

A driver.

Explanation:

Using a driver while at least 350 yds away is better than using a iron, because it will be a waste of the par 4 as it is not as powerful as the driver.

3 0
2 years ago
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