Answer:
D. 0.7 would be wild-type healthy
E. 0.3 would be affected Gg
Explanation:
Using the Punnett square we cross an homozygous male (gg), that is always healthy vs an heterozygous female (Gg). The result is 2 gg individuals, and 2 Gg individuals. Both gg individuals are healthy.
In a population of 1000 Gg individuals, 600 show the Gumball phenotype (unhealthy). It means that from the two heterozygous Gg (from the Punnett square), 1.2 show the unhealthy phenotype.
Again, from the Punnett square we have 4 individuals, that represent the 100%. 1.2 are unhealthy Gg, and represent 30% in F1.
This 30%, is equivalent to 0.3, that is the option E.
100 - 30 % = 70 %. This is 0.7 for healthy wild-type, option D.
Answer:
Mass of Little Sister = 44.17 kg
Explanation:
From Newton's second law of motion, the magnitude of force applied on the sled is given by the following formula:
F = ma
where,
F = Force Applied = 120 N
a = Acceleration = 2.3 m/s²
m = Mass of Sled + Mass of Little Sister = 8 kg + Mass of Little Sister
Therefore,
120 N = (2.3 m/s²)(8 kg + Mass of Little Sister)
(120 N)/(2.3 m/s²) = 8 kg + Mass of Little Sister
Mass of Little Sister = 52.17 kg - 8 kg
<u>Mass of Little Sister = 44.17 kg</u>
Answer:
1.07 x 10⁻⁸N
Explanation:
Given parameters:
Mass 1 = 200kg
Mass 2 = 500kg
Distance of separation = 25m
Unknown:
Gravitational attraction between the two bodies = ?
Solution:
To solve this problem, we use the equation of the universal gravitation;
F =
G is the universal gravitation constant = 6.67 x 10⁻¹¹Nm²kg⁻²
r is the distance
Now insert the parameters and solve;
F =
= 1.07 x 10⁻⁸N
Answer:
1.024 × 10⁸ m
Explanation:
The velocity v₀ of the orbit 8RE is v₀ = 8REω where ω = angular speed.
So, ω = v₀/8RE
For the orbit with radius R for it to maintain a circular orbit and velocity 2v₀, we have
2v₀ = Rω
substituting ω = v₀/8RE into the equation, we have
2v₀ = v₀R/8RE
dividing both sides by v₀, we have
2v₀/v₀ = R/8RE
2 = R/8RE
So, R = 2 × 8RE
R = 16RE
substituting RE = 6.4 × 10⁶ m
R = 16RE
= 16 × 6.4 × 10⁶ m
= 102.4 × 10⁶ m
= 1.024 × 10⁸ m
Answer:
A driver.
Explanation:
Using a driver while at least 350 yds away is better than using a iron, because it will be a waste of the par 4 as it is not as powerful as the driver.