Answer:
6.5 kW
Explanation:
Input power = 20 kW = 20000 W
h = 45 m
Volume flow per second = 0.03 m^3 /s
mass flow per second = volume flow per second x density of water
= 0.03 x 1000 = 30 kg/s
Output power = m g h / t = 30 x 10 x 45 = 13500 W
Power converted in form of heat = Input power - Output power
= 20000 - 13500 = 6500 W = 6.5 kW
Thus, mechanical power converted into heat is 6.5 kW.
Answer:
The other two small angles are 45° each
Explanation:
Given data in the problem:
The triangle is a right triangle
thus,
one of the angle is 90°
now,
let the other two angles be x and y
thus,
it is given that:
x = 2y - 45°
also in a triangle
sum of all the angles = 180°
thus,
x + y + 90° = 180°
or
x + y = 90°
now, substituting the value of x from the above relation between x and y, we get
2y - 45° + y = 90°
or
3y = 135°
or
y = 45°
also,
x = 2y - 45°
or
x = 2 × (45°) - 45°
or
x = 45°
hence, <u>the other two small angles are 45° each</u>
Answer:
Explanation:
As we stir the pot of soup by a metal spoon which is a conductor, it conducts the heat and starts heating after some time the temperature of the spoon rises and we are not able to hold the spoon and we get burns.
Answer:
Explanation:
a ) No of turns per metre
n = 450 / .35
= 1285.71
Magnetic field inside the solenoid
B = μ₀ n I
Where I is current
B = 4π x 10⁻⁷ x 1285.71 x 1.75
= 28.26 x 10⁻⁴ T
This is the uniform magnetic field inside the solenoid.
b )
Magnetic field around a very long wire at a distance d is given by the expression
B = ( μ₀ /4π ) X 2I / d
= 10⁻⁷ x 2 x ( 1.75 / .01 )
= .35 x 10⁻⁴ T
In the second case magnetic field is much less. It is due to the fact that in the solenoid magnetic field gets multiplied due to increase in the number of turns. In straight coil this does not happen .
<span>First, we use the kinetic energy equation to create a formula:
Ka = 2Kb
1/2(ma*Va^2) = 2(1/2(mb*Vb^2))
The 1/2 of the right gets cancelled by the 2 left of the bracket so:
1/2(ma*Va^2) = mb*Vb^2 (1)
By the definiton of momentum we can say:
ma*Va = mb*Vb
And with some algebra:
Vb = (ma*Va)/mb (2)
Substituting (2) into (1), we have:
1/2(ma*Va^2) = mb*((ma*Va)/mb)^2
Then:
1/2(ma*Va^2) = mb*(ma^2*Va^2)/mb^2
We cancel the Va^2 in both sides and cancel the mb at the numerator, leving the denominator of the right side with exponent 1:
1/2(ma) = (ma^2)/mb
Cancel the ma of the left, leaving the right one with exponent 1:
1/2 = ma/mb
And finally we have that:
mb/2 = ma
mb = 2ma</span>
