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astra-53 [7]
2 years ago
7

Explain how scientists know that elephants and hyraxes are related. Be sure to include anatomical similarities as well as fossil

evidence in your explanation.
Physics
2 answers:
leonid [27]2 years ago
8 0

<em>Hyraxes, elephants and dugongs are more closely related to one another than to any other living animal.  Well, that's not exactly true. The closest surviving relative of the dugong is the manatee, a fresh-water, New-World version of itself. Apart from this, and the fact that there are two species of elephant and several of hyrax, it's absolutely true. Hyraxes, elephants and dugongs evolved from a single common ancestor.</em>

                                          Hope This Helps

mojhsa [17]2 years ago
7 0

This is the exact answer:

Elephants and hyraxes share many anatomical similarities. They both have flat, hoof-like nails on the tips of their toes. They also have four toes on their front feet and three toes on their rear feet. Elephants and hyraxes both develop tusks from their incisor teeth instead of their canine teeth, like most other mammals. In addition to the anatomical similarities, fossil evidence has revealed that hyraxes and elephants share a 40-million-year-old ancestor.

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If you touch the two terminals of a power supply with your two fingertips on opposite hands, the potential difference will produ
LiRa [457]

Answer:

Yes the body will receive a dangerous shock in both cases.

Explanation:

Different parts of the body has different resistance. skin has the high resistance as compared to other organs of the body.

Dry skin has high resistance than wet skin this is because water is relatively good conductor of electricity, it adds parallel path to the current flow and hence reduces skin resistance.

Dry hands body has approximately 500 kΩ resistance and if 120 V electricity supply current received will be:

I = V/R= 120/ 500*10^3

I= 0.24 mA

Even the current seems is much lower than the safe zone but this is the case in case of DC voltage in case of AC voltage the body will receive a shock this is because the skin pass more current when the voltage is changing i.e. AC.

Similarly for wet hands body resistance is 1 kΩ. so the current through the body seems to be:

I = 120 / 1000

I = 12 mA

The current is higher than safe zone so the body will receive a dangerous shock.

7 0
2 years ago
What factors affect attractive force
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Two Factors That Affect How Much Gravity Is on an Object. Gravity is the force that gives weight to objects and causes them to fall to the ground when dropped. Two major factors, mass and distance, affect the strength of gravitational force on an object.

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2 years ago
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A semi is traveling down the highway at a velocity of v = 26 m/s. The driver observes a wreck ahead, locks his brakes, and begin
Dovator [93]

Answer:

fcosθ + Fbcosθ  =Wtanθ

Explanation:

Consider the diagram shown in attachment

fx= fcosθ (fx: component of friction force in x-direction ; f: frictional force)

Fbx= Fbcosθ ( Fbx: component of braking force in x-direction ; Fb: braking force)

Wx= Wtanθ (Wx: component of weight in x-direction ; W: Weight of semi)

sum of x-direction forces = 0

fx+ Fbx=Wx

fcosθ + Fbcosθ  =Wtanθ

7 0
2 years ago
A kite is 100m above the ground. If there are 200m of string out, what is the angle between the string and the horizontal? (Assu
belka [17]

Answer:

the answer is 30°

Explanation:

due to:

sin law of sines

\frac{sin 90}{200} =\frac{sin\beta }{100}\\arcsin(100\frac{sin90}{200} )= 30°

3 0
2 years ago
3. What conclusion can you make about the electric field strength between two parallel plates? Explain your answer referencing P
KIM [24]

Answer:

From the relation above we can conclude that the  as the distance between the two plate increases the electric field strength decreases

Explanation:

I cannot  find any attached photo, but we can proceed anyways theoretically.

The electric field strength (E) at any point in an electric field is the force experienced by a unit positive charge (Q) at that point

i.e

E=\frac{F}{Q}

But the force F

F= \frac{kQ1Q2}{r^2}

But the electric field intensity due to a point charge Q at a distance r meters away is given by

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<em>From the relation above we can conclude that the  as the distance between the two plate increases the electric field strength decreases</em>

6 0
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