Explain how scientists know that elephants and hyraxes are related. Be sure to include anatomical similarities as well as fossil
2 answers:
You might be interested in
(a) Greater
The frequency of the nth-harmonic on a string is an integer multiple of the fundamental frequency, :
So we have:
- On wire A, the second-harmonic has frequency of , so the fundamental frequency is:
- On wire B, the third-harmonic has frequency of , so the fundamental frequency is
So, the fundamental frequency of wire A is greater than the fundamental frequency of wire B.
(b)
For standing waves on a string, the fundamental frequency is given by the formula:
where
v is the speed at which the waves travel back and forth on the wire
L is the length of the string
(c) Greater speed on wire A
We can solve the formula of the fundamental frequency for v, the speed of the wave:
We know that the two wires have same length L. For wire A, , while for wave B,
, so we can write the ratio between the speeds of the waves in the two wires:
So, the waves travel faster on wire A.
Answer:
(a) 1.87 x 10⁻⁴ m/s
(b) 0.013V
Explanation:
(a) Drift speed, , is the average velocity that a charged particle can have due to an electric field. For a given current, I, the drift velocity is given by;
=
----------------(i)
Where;
q = amount of charge
n = free charge density
A = cross-sectional area of the wire
But current density, J, is the electric current per unit cross-section area. This is also equal to the ratio of the electric field, E, to the resistivity, p, of the material of the wire. i.e
J = =
Equation (i) can then be written as follows;
=
=
=
---------------------(ii)
From the question;
E = 0.0520N/C
p = 1.72 x 10⁻⁸ Ωm
n = 8.5 x 10²⁸ electrons/m³
c = charge on electron = 1.9 x 10⁻¹⁹C
Substitute these values into equation (ii) as follows;
=
= 1.87 x 10⁻⁴ m/s
(b) The potential difference, V, is given by the product of the electric field and the distance, d, between the two points in the wire. i.e
V = E x d [where d = 25.0cm = 0.25m]
V = 0.0520 x 0.25
V = 0.013V