Question

A water-skier with weight Fg = mg moves to the right with acceleration a. A horizontal tension force T is exerted on the skier by the rope, and a horizontal drag forcc Fa is cxertcd by thc watcr on the ski. The water also exerts a vertical lift force L on the skier. Which of the following are correct relationships between the forces exerted on the skier-ski system? Select two answers. (A) T-Fd = ma (B) L-Fg=ma (C) L- =0 (D) T- Fd 0

Answer 1

Answer:

The correct relationships are T-fg=ma and L-fg=0.

(A) and (C) is correct option.

Explanation:

Given that,

Weight Fg = mg

Acceleration = a

Tension = T

Drag force = Fa

Vertical force = L

We need to find the correct relationships

Using balance equation

In horizontally,

The acceleration is a

$T-Fd=ma$...(I)

In vertically,

No acceleration

$w=L$

$mg-L=0$

Put the value of mg

$L-fg=0$....(II)

Hence,  The correct relationships are T-fg=ma and L-fg=0.

(A) and (C) is correct option.