Question

Monica pulls her daughter Jessie in a bike trailer. The trailer and Jessie together have a mass of 25 kg. Monica starts up a 100-m-long slope that's 4.0 m high. On the slope, Monica's bike pulls on the trailer with a constant force of 8.0 N. They start out at the bottom of the slope with a speed of 5.3 m/s.

Answer 1

Answer:

This is their velocity on the top of the slope $v=3.7 \frac{m}{s}$

Explanation:

The problem doesn't have final question however is an example of conservation of energy

$Kf+(Ug)f=Ki+(Ug)j+W$

And given from the problem to know the final velocity

$Yi=0\\vi=5.3 \frac{m}{s}\\ m=25kg\\F=8.0N\\d=100m\\Yf=4m$

$Kf+(Ug)f=Ki+(Ug)j+W$

$\frac{1}{2}*m*vf ^{2}+m*g*Yf=\frac{1}{2}*m*vi^{2}+m*g*Yi+W\\\frac{1}{2}*m*vf ^{2}+m*g*Yf=\frac{1}{2}*m*vi^{2}+W\\\frac{1}{2}*m*vf ^{2}=\frac{1}{2}*m*vi^{2}+W-m*g*Yf\\vf ^{2}=vi^{2}+2*\frac{W}{m}+2*g*Yf\\vf ^{2}=(5.3\frac{m}{s})^{2} +\frac{2*F*d}{m}-2*9.8\frac{m}{s^{2}}*4m\\vf ^{2}=(5.3\frac{m}{s})^{2} +\frac{2*8.0N*100m}{25kg}-2*9.8\frac{m}{s^{2}}*4m\\vf=\sqrt{13.69 \frac{m^{2} }{s^{2} } } \\vf=3.7 \frac{m}{s}$