Below are the choices that can be found in the other sources:
A. diffraction
<span>B. refraction </span>
<span>C. reflection </span>
<span>D. transmission
</span>
The answer is diffraction. It means that <span>the process by which a beam of light or other system of waves is spread out as a result of passing through a narrow aperture or across an edge, typically accompanied by interference between the wave forms produced.</span>
<h3><u>Answer;</u></h3>
<em>Work = 125 joules </em>
<h3><u>Explanation and solution</u>;</h3>
- Work is the product of force and the distance covered. Therefore, Work = force × distance.
- Work is measured in joules.
- Work is also a change in energy, such that work is done when energy changes, so when kinetic energy, or potential energy changes the there is work being done.
Thus; kinetic energy = work done
Kinetic energy = 1/2mv²
= 1/2 × 10× 5²
= 5 × 25
= 125 joules
Hence, work done is 125 joules.
Answer:
Explanation:
When the screw is turned by two turns then change in the length of the wire is given as
now we know by the formula of Young's modulus
so we have
Answer:
Density of body = 0.25g/cc
Explanation:
Given:
Volume submerged in water = 3/4
Find:
Density Of Body
Computation:
Density of body = fraction of body in liquid x density of water
Density of body = [1-3/4]1
Density of body = 0.25g/cc
Answer:
Explanation:
Given that,
Height of the bridge is 20m
Initial before he throws the rock
The height is hi = 20 m
Then, final height hitting the water
hf = 0 m
Initial speed the rock is throw
Vi = 15m/s
The final speed at which the rock hits the water
Vf = 24.8 m/s
Using conservation of energy given by the question hint
Ki + Ui = Kf + Uf
Where
Ki is initial kinetic energy
Ui is initial potential energy
Kf is final kinetic energy
Uf is final potential energy
Then,
Ki + Ui = Kf + Uf
Where
Ei = Ki + Ui
Where Ei is initial energy
Ei = ½mVi² + m•g•hi
Ei = ½m × 15² + m × 9.8 × 20
Ei = 112.5m + 196m
Ei = 308.5m J
Now,
Ef = Kf + Uf
Ef = ½mVf² + m•g•hf
Ef = ½m × 24.8² + m × 9.8 × 0
Ef = 307.52m + 0
Ef = 307.52m J
Since Ef ≈ Ei, then the rock thrown from the tip of a bridge is independent of the direction of throw
