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Alexus [3.1K]
2 years ago
8

Liz puts a 1 kg weight and a 10 kg on identical sleds. She then applies a 10N force to each sled. Which does not explain why the

smaller weight accelerate faster?
A) The larger mass spends more force overcoming inertia.
B) The smaller weight exerts less frictional force to overcome.
C) The acceleration depends directly on the mass of the object.
D) The motion of the sled relates to action of unbalanced forces.

Physics
2 answers:
Serga [27]2 years ago
4 0

Answer:

c. the acceleration depends directly on the mass of the objects

Explanation:

Mariana [72]2 years ago
3 0
Answer: C

Explanation:
The acceleration does not depend directly on the mass of the object.

Newton's Law is Force = Mass x Acceleration.
Therefore, Acceleration  = Force/Mass

The same force is applied in both cases.
Therefore acceleration is inversely proportional to mass.
As mass decreases, acceleration increases.

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To solve this problem it is necessary to apply the concepts related to thermal stress. Said stress is defined as the amount of deformation caused by the change in temperature, based on the parameters of the coefficient of thermal expansion of the material, Young's module and the Area or area of the area.

F = AY\alpha \Delta T

Where

A = Cross-sectional Area

Y = Young's modulus

\alpha= Coefficient of linear expansion for steel

\Delta T= Temperature Raise

Our values are given as,

A = 4.45cm^2

T = 37K

\alpha = 1.17*10^{-5}K^{-1}

Y = 200*10^9Gpa

Replacing we have,

F = (4.45*10^{-4})(200*10^9)(1.17*10^{-5})(37)

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Therefore the size of the force developing inside the steel rod when its temperature is raised by 37K is 38526.1N

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A cliff diver running 3.60 m/s dives out horizontally from the edge of a vertical cliff and reaches the water below 2.00 s later
mart [117]

Explanation:

It is given that,

The horizontal speed of a cliff diver, v_x=3.6\ m/s

It reaches the water below 2.00 s later, t = 2 s

Let d_x is the distance where the diver hit the water. It can be calculated as follows :

d_x=v_x\times t\\\\=3.6\times 2\\\\=7.2\ m

Let d_y is the height of the cliff. It can be calculated using second equation of motion as follows :

d_y=u_yt+\dfrac{1}{2}gt^2\\\\d_y=\dfrac{1}{2}\times 9.8\times 2^2\\\\=19.6\ m

So, the cliff is 19.6 m high and it will hit the water at a distance of 19.6 m.

8 0
1 year ago
a 250 mH coil of negligible resistance is connected to an AC circuit in which as effective current of 5 mA is flowing. if the fr
mash [69]

Answer:

the inductive reactance of the coil is 1335.35 Ω

Explanation:

Given;

inductance of the coil, L = 250 mH = 0.25 H

effective current through the coil, I = 5 mA

frequency of the coil, f = 850 Hz

The inductive reactance of the coil is calculated as;

X_l = \omega L = 2\pi f L\\\\X_l = 2\pi \times 850 \times 0.25\\\\X_l = 1335.35 \ ohms

Therefore, the inductive reactance of the coil is 1335.35 Ω

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