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2 years ago

A zebra runs across a field at a constant speed of 14m/s how far does the zebra go in 8 seconds?

Physics

2 answers:

Ratling [72]2 years ago

3 0

Answer:

112m/s

Explanation:

14x8=112 therefore meaning the zebra would run 112m/s

RoseWind [281]2 years ago

3 0

A zebra runs across a field at a constant speed of 14 m/s. The zebra would run 112 m in 8 seconds.

Explanation: 

According to Kinematics, the distance travelled is given by the product of speed and time. Here, the speed given as 14 m/s, and time is 8 seconds. Now, the equation is as follows,

$\text {velocity} = \frac{\text {distance}(s)}{\text {time}(t)}$

The required term to find as per the question is distance, so rearranging the above equation, we get,

$s = v e l o c i t y \times t$

By substituting the given values, we get, how much distance the zebra can run in time period of 8 seconds as,

Distance, $s = 14 \times 8 = 112 m$

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Nuetrik [128]

Answer:

the expected distance is 4.32 m

Explanation:

given data

half life time = 1.8 × $10^{-8}$ s

speed = 0.8 c = 0.8 × 3 × $10^{8}$

to find out

expected distance over

solution

we know c is speed of light in air is 3 × $10^{8}$ m/s

we calculate expected distance by given formula that is

expected distance = half life time × speed .........1

put here all these value

expected distance = half life time × speed

expected distance = 1.8 × $10^{-8}$ × 0.8 × 3 × $10^{8}$

expected distance = 4.32

so the expected distance is 4.32 m

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2 years ago

A rocket exhausts fuel with a velocity of 1500m/s, relative to the rocket. It starts from rest in outer space with fuel comprisi

babunello [35]

Answer:

v= 2413.5 m/s

Explanation:

maximum change of speed of rocket

=(initial exhaust velocity)×ln [(initialmass/finalmass)]

let initial mass= m

final mass = m-m(4/5) = m/5

[since the 80% of mass which is fuel is exhausted]

V-0 = 1500 ln (1/0.2)

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therefore, its exhaust speed v= 2413.5 m/s

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2 years ago

Read 2 more answers

You are pulling your little sister on her sled across an icy (frictionless) surface. When you exert a constant horizontal force

Tpy6a [65]

Answer:

Mass of Little Sister = 44.17 kg

Explanation:

From Newton's second law of motion, the magnitude of force applied on the sled is given by the following formula:

F = ma

where,

F = Force Applied = 120 N

a = Acceleration = 2.3 m/s²

m = Mass of Sled + Mass of Little Sister = 8 kg + Mass of Little Sister

Therefore,

120 N = (2.3 m/s²)(8 kg + Mass of Little Sister)

(120 N)/(2.3 m/s²) = 8 kg + Mass of Little Sister

Mass of Little Sister = 52.17 kg - 8 kg

Mass of Little Sister = 44.17 kg

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2 years ago

4. Dr. Copus is in charge of the cognition department at the University of Wisconsin-Madison. A new drug named Mem-Reen has beco

MrMuchimi

Answer:

See the answer below

Explanation:

Independent variable: Type of drug (Mem-Reen or placebo)

Dependent variable: memories

Experimental group: The group that was given Mem-Reen

Control group: The group that was given placebo

Constants: Food, hours of sleep, memory test procedures.

The independent variable is an input variable that produces effects on the dependent variable. As the variable is changed, it produces different effects on the dependent variable.

The dependent variable is the actual variable that is measured during an experiment. It is the main purpose of setting-up of an experiment.

The experimental group is also referred to as the treatment group while the control group is the group that does not receive treatment at all or they receive fake treatment/placebo.

Constants are unchanging variables included in experiments. They remain unchanged both in the treatment and the control group, otherwise, the outcome of the experiment will be unreliable.

5 0

2 years ago

A wire of 1mm diameter and 1m long fixed at one end is stretched by 0.01mm when a lend of 10 kg is attached to its free end.calc

Otrada [13]

Answer:

E = 1.25×10¹³ N/m²

Explanation:

Young's modulus is defined as:

E = stress / strain

E = (F / A) / (dL / L)

E = (F L) / (A dL)

Given:

F = 10 kg × 9.8 m/s² = 98 N

L = 1 m

dL = 10⁻⁵ m

A = π/4 (0.001 m)² = 7.85×10⁻⁷ m²

Solve:

E = (98 N × 1 m) / (7.85×10⁻⁷ m² × 10⁻⁵ m)

E = 1.25×10¹³ N/m²

Round as needed.

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2 years ago