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Nutka1998 [239]
2 years ago
6

An object starts from rest and slides with negligible friction down an air track tipped at an angle theta from the horizontal. A

student records values of the object's position along the track at various times. the value of theta can best be determined from which of the following? the y-intercept of a graph of position as a function of time the y-intercept of a graph of position as a function of the square of time the slope of a graph of position as a function of time the slope of a graph of position as a function of the square of time

Physics
1 answer:
Alex Ar [27]2 years ago
6 0

Answer:

The value of θ can be determined by slope of graph as function of square of time.

Explanation:

Lets take

Mass = m

Angle of inclination =θ

From diagram

mg sinθ = m a

So

a=g sinθ

We know that

S=ut+\dfrac{1}{2}at^2

Given that block is in rest position initially.

u= 0

S=\dfrac{1}{2}(gsin\theta ) t^2

We can say that

S∝ t²      If we assume that t and x and S as y y= m x

S=\dfrac{1}{2}(gsin\theta ) t^2

Here slope ,m

m=\dfrac{1}{2}(gsin\theta )

So the value of θ can be determined by slope of graph as function of square of time.

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Answer:

Time taken = 8.25 second

Explanation:

Given:

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0 = 30 + (3.6363)t

Time taken = 8.25 second

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Consider four different oscillating systems, indexed using i = 1 , 2 , 3 , 4 . Each system consists of a block of mass mi moving
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2 years ago
A world class runner can run long distances at a pace of 15 km/hour. That runner expends 800 kilocalories of energy per hour. a)
Talja [164]
<h2>Answer:</h2>

(a) 933.33W

(b) 3.36 x 10⁶J

<h2>Explanation:</h2>

(a) Power is the time rate of change of energy.

In the question, the runner expends 800 kilocalories (kcal) of energy in one hour (h).

That means that power expended is 800 kcal / h.

To get the power in Watts, we convert 800 kcal/h to Joules per second (J/s) as follows;

(i) First convert kcal to Joules (J)

1 cal = 4.2 J

1 kcal = 1 x 1000 cal = 1 x 1000 cal x 4.2 J / 1 cal = 4200 J

(ii) Then convert 1 hour to second (s)

1 h = 3600s

(iii) Now convert 800 kcal/h to J/s

800 kcal / h = \frac{800 * 1 k cal}{1 h} = \frac{800 * 4200J}{3600s} = 933.33J/s = 933.33W

Therefore, the power expended in J/s (or in Watts) is 933.33

(b) According to the question, the runner can run 15km in 1 hour and will expend a power of 933.33W. To calculate the energy expended at this time, we use the formula;

E = P x t             -------------------(ii)

Where;

E = Energy

P = Power = 933.33W

t = time taken = 1 hour = 36000s

Substitute these values into equation (ii) as follows;

E = 933.33 x 3600

E = 3359988 J

E = 3.36 x 10⁶ J

Therefore, the total energy is 3.36 x 10⁶J

7 0
2 years ago
A thug pushes some 100 kg punk with 300 N of force. How much is the punk accelerated?
astra-53 [7]

Answer:

Acceleration generate by punk = 3 m/s²

Explanation:

Given:

Weight of punk = 100 Kg

Force applied on punk = 300 N

Find:

Acceleration generate by punk = ?

Computation:

Acceleration = Force / Mass

Acceleration generate by punk = Force applied on punk / Weight of punk

Acceleration generate by punk = 300 N / 100 Kg

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5 0
2 years ago
The two structural members, one of which is in tension and the other in compression, exert the indicated forces on joint O. Dete
Inessa05 [86]

Answer:

R = 3.606 KN, θ = 24°

Explanation:

Resolving the forces to the x-direction

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Resolving the forces to the y-direction

Ry = -3sin60 + 2sin30

= -2.6 + 1 = -1.6 KN

Getting the resultant of the two forces

R = \sqrt{Rx^2 + Ry^2}

Substituting the values of Rx and Ry, we obtain

R = 3.606 KN

tanθ = Ry/Rx = | -1.6/3.232 |

Then we have θ = 24°

6 0
2 years ago
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