The two structural members, one of which is in tension and the other in compression, exert the indicated forces on joint O. Dete
1 answer:
Answer:
R = 3.606 KN, θ = 24°
Explanation:
Resolving the forces to the x-direction
Rx = 3cos60 + 2cos30
= 1.5 + 1.732 = 3.232 KN
Resolving the forces to the y-direction
Ry = -3sin60 + 2sin30
= -2.6 + 1 = -1.6 KN
Getting the resultant of the two forces
R =
Substituting the values of Rx and Ry, we obtain
R = 3.606 KN
tanθ = Ry/Rx = | -1.6/3.232 |
Then we have θ = 24°
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(a) north
We can treat the aircraft as a single point charge moving in a magnetic field. In this case, the magnetic force exerted on the plane is
where
is the charge on the plane
v = 660 m/s is the velocity
is the magnitude of the magnetic field
is the angle between the direction of motion of the jet and of the magnetic field
Substituting,
The direction can be found by using Fleming's left hand rule. We have:
- index finger: magnetic field direction (straight up)
- middle finger: velocity of the plane (due west)
- force: thumb --> north
(b) Not negligible
As we can see from part (a), the magnitude of the force is not really big, so the effects are negligible.
For instance, we can compare this force with the weight of a plane. If we take a Boeing 737, its mass is about 80,000 kg, so its weight is
As we can see, this is several orders of magnitude bigger than the magnetic force calculated at point (a), so the effects of the magnetic force are negligible.
Answer:
2 x 10⁻³ volts
Explanation:
B = magnetic of magnetic field parallel to the axis of loop = 1 T
= rate of change of area of the loop = 20 cm²/s = 20 x 10⁻⁴ m²
θ = Angle of the magnetic field with the area vector = 0
E = emf induced in the loop
Induced emf is given as
E = B
E = (1) (20 x 10⁻⁴ )
E = 2 x 10⁻³ volts
E = 2 mV