Answer:
To both observers, the land opposite them is moving to the right.
Explanation:
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Vx = 2*cos30 = 1.73m's
Other words:
D = Vo*t = 1.4 * 21 = 31.5m. @ 30 Deg.
Dy = 31.5*sin30 = 15.75 m.
Answer:
Flow Rate = 80 m^3 /hours (Rounded to the nearest whole number)
Explanation:
Given
- Hf = head loss
- f = friction factor
- L = Length of the pipe = 360 m
- V = Flow velocity, m/s
- D = Pipe diameter = 0.12 m
- g = Gravitational acceleration, m/s^2
- Re = Reynolds's Number
- rho = Density =998 kg/m^3
- μ = Viscosity = 0.001 kg/m-s
- Z = Elevation Difference = 60 m
Calculations
Moody friction loss in the pipe = Hf = (f*L*V^2)/(2*D*g)
The energy equation for this system will be,
Hp = Z + Hf
The other three equations to solve the above equations are:
Re = (rho*V*D)/ μ
Flow Rate, Q = V*(pi/4)*D^2
Power = 15000 W = rho*g*Q*Hp
1/f^0.5 = 2*log ((Re*f^0.5)/2.51)
We can iterate the 5 equations to find f and solve them to find the values of:
Re = 235000
f = 0.015
V = 1.97 m/s
And use them to find the flow rate,
Q = V*(pi/4)*D^2
Q = (1.97)*(pi/4)*(0.12)^2 = 0.022 m^3/s = 80 m^3 /hours
Answer:
Explanation:
temperature (T) = 25 degrees
volume of water (v) = 2 L = 2000 mL
density of water = 0.997 g/mL
density of ice = 0.917 g/mL
we can get the mass of the water and the use it to get the volume when it freezes to ice, this is because the mass remains the same irrespective of the change of state.
- mass of water = volume x density = 2000 x 0.997 = 1994 g
- volume of ice = mass/density = 1994 / 0.917 = 2174.5 mL = 2.175 L
Ammeter in series at any side as required since it is bilateral and voltmeter is connected in parallel to measure voltage drop across it.