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Kryger [21]
2 years ago
12

The heaviest wild lion ever measured had a mass of 313 kg. Suppose this lion is walking by a lake when it sees an empty boat flo

ating at rest near the shore. The curious lion jumps into the boat with a speed of 6.00 m/s, causing the boat with the lion in it to move away from the shore with a speed of 2.50 m/s. How much kinetic energy is dissipated in this inelastic collision?
Physics
1 answer:
11Alexandr11 [23.1K]2 years ago
3 0

Answer:

The kinetic energy dissipated is 3286.5 J

Explanation:

K.E before collision = 1/2m1v1^2 = 1/2×313×6^2 = 5634 J

K.E after collision = 1/2(m1+m2)v2^2

From the law of conservation of momentum:

m1+m2 = m1v1/v2 = 313×6/2.5 = 751.2 kg

K.E after collision = 1/2×751.2×2.5^2 = 2347.5 J

K.E dissipated = 5634 J - 2347.5 J = 3286.5 J

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E = (1/2)CV²
1 = (1/2)*(2*10⁻⁶)V²
10⁶ = V²
1000 = V

You should charge it to 1000 volts to store 1.0 J of energy.
6 0
2 years ago
in physics lab, a cube slides down a frictionless incline as shown in the figure below, and elastically strikes another cube at
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2 years ago
Two sources emit beams of light of wavelength 550 nm. The light from source A has an intensity of 10 μW/m2, and the light from s
alexira [117]

Answer:

<em>A) Beam B carries twice as many photons per second as beam A.</em>

Explanation:

If we have two waves with the same wavelength, then their intensity is proportional to their power, or the energy per unit time.

We also know that the amount of photon present in an electromagnetic beam is proportional to the energy of the beam, hence the amount of beam per second is proportional to the power.

With these two facts, we can say that the intensity is a measure of the amount of photon per second in an electromagnetic beam. So we can say that <em>beam B carries twice as more power than beam A, or Beam B carries twice as many photons per second as beam A.</em>

3 0
2 years ago
Have you ever chewed on a wintergreen mint in front of a mirror in the dark? If you have, you may have noticed some sparks of li
lutik1710 [3]

Answer:

Part a)

E = 3.66 eV

Part b)

\lambda = 508.5 nm

Explanation:

Part a)

change in the energy due to decay of photon is given as

E = h\nu

here we know that

\nu = 8.88 \times 10^{14} Hz

now we have

E = (6.6 \times 10^{-34})(8.88 \times 10^{14})

E = 5.86 \times 10^{-19} J

E = 3.66 eV

Part b)

While electron return to its ground state it will emit a photon of energy 2/3rd of the total energy

so we have

\Delta E = \frac{2}{3}(3.66 eV)

\Delta E = 2.44 eV

now to find the wavelength we have

\Delta E = \frac{hc}{\lambda}

2.44 = \frac{1242}{\lambda}

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3 0
2 years ago
A rocket moves upward, starting from rest with an acceleration of +29.4 for 3.98 s. it runs out of fuel at the end of the 3.98 s
topjm [15]
U = 0, initial upward speed
a = 29.4 m/s², acceleration up to 3.98 s
a = -9.8 m/s², acceleration after 3.98s

Let h₁ =  the height at time t, for t ≤ 3.98 s
Let h₂ =  the height at time t > 3.98 s

Motion for  t ≤ 3.98 s:
h₁ = (1/2)*(29.4 m/s²)*(3.98 s)² = 232.854 m
Calculate the upward velocity at t = 3.98 s
v₁ = (29.4 m/s²)*(3.98 s) = 117.012 m/s

Motion for t  > 3.98 s
At maximum height, the upward velocity is zero.
Calculate the extra distance traveled before the velocity is zero.
(117.012 m/s)² + 2*(-9.8 m/s²)*(h₂ m) = 0
h₂ = 698.562 m

The total height is
h₁ + h₂ = 232.854 + 698.562 = 931.416 m

Answer: 931.4 m (nearest tenth)

6 0
2 years ago
Read 2 more answers
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